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laiz [17]
3 years ago
11

The picture below shows a wheelbarrow. Using a wheelbarrow can make it easier to lift a heavy object by

Physics
1 answer:
timofeeve [1]3 years ago
8 0

Answer:

B IS CORRECT

Explanation:

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A thin film soap bubble (n=1.35) is floating in air. If the thickness of the bubble wall is 300nm, which of the following wavele
iren [92.7K]

Answer:

540 nm

Explanation:

According to the question,

The refractive index of the soap bubble, n=1.35.

The thickness of the soap bubble wall is, t=300 nm.

Now, for constructive interference of soap bubble.

2nt=(m+\frac{1}{2})\lambda.

Now for first order m=1.

Therfore,

\lambda =\frac{4}{3} tn

Substitute all the variables in the above equation.

\lambda =\frac{4}{3} (1.35)(300 nm).

Therefore,

\lambda =540 nm.

Therefore the visible light wavelength which is strongly reflected is 540 nm.

6 0
3 years ago
Which situations might cause two observers (A and B) to measure different frequencies for the same vibrating object? Select the
Alex787 [66]

We want to explain why two different observes may measure different frequencies for the same vibrating object.

We will see that the two correct options are:

  • <em>Observer A is stationary and Observer B is moving.</em>
  • <em>Observer A and Observer B are moving at different speeds relative to each other.</em>

<em />

Let's assume that the vibrating object is a guitar string. Thus, the string makes a noise, and from that noise, we can estimate the frequency at which the string vibrates.

Now there appears a really cool effect, called the Doppler Effect. It says that the apparent change of frequency is <u>due to the motion of the observer or the source of the frequency (or both).</u>

For example, if you move towards the vibrating string, the perceived frequency will be larger, and you will hear a "higher" sound.

While if you move away from the string, the opposite happens, and you will hear a "lower" sound.

Then the only thing that impacts in how we perceive the frequency is our velocity relative to the source.

So, why do observers A and B measure different frequencies?

The two correct answers are:

  • <em>Observer A is stationary and Observer B is moving.</em>
  • <em>Observer A and Observer B are moving at different speeds relative to each other.</em>

If you want to learn more, you can read:

brainly.com/question/17107808

6 0
3 years ago
What is the awnser to that question
Olegator [25]
The answers To your question is c
8 0
3 years ago
Read 2 more answers
A student moves a box across the floor by exerting 56.7 N of force and doing 195 J of
Paha777 [63]

Answer:

A. 3.4 m

Explanation:

Given the following data;

Force = 56.7N

Workdone = 195J

To find the distance

Workdone is given by the formula;

Workdone = force * distance

Making "distance" the subject of formula, we have;

Distance = \frac {workdone}{force}

Substituting into the equation, we have;

Distance = \frac {195}{56.7}

Distance = 3.4 meters.

8 0
3 years ago
Long ding dong what it do?
Andre45 [30]

Answer:

nun wbu

Explanation:

3 0
3 years ago
Read 2 more answers
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