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laiz [17]
3 years ago
11

The picture below shows a wheelbarrow. Using a wheelbarrow can make it easier to lift a heavy object by

Physics
1 answer:
timofeeve [1]3 years ago
8 0

Answer:

B IS CORRECT

Explanation:

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In this first example of constant accelerated motion, we will simply consider a car that is initially traveling along a straight
algol13

Answer:

v_{f} =25m/s

Explanation:

Kinematics equation for constant acceleration:

v_{f}  =v_{o} + at=15+2*5=25m/s

4 0
2 years ago
Freight trains can produce only relatively small acceleration and decelerations. (a) what is the final velocity (in m/s) of a fr
m_a_m_a [10]
(a) We will use the equation v = u + at
Initial velocity u = 5.00 m/s 
Acceleration a = 0.0600 m/s² 
time = 8 min = 8 x 60 = 480 s 
Final velocity 
= u + at 
= 5.00 + 0.0600(480) 
= 33.8 m/s

The final velocity is 33.8 m/s
5 0
2 years ago
Read 2 more answers
Three people pull simultaneously on a stubborn donkey. Jack pulls eastward with a force of 64.7 N, Jill pulls with 61.5 N in the
USPshnik [31]

Answer:

 F = 241.8 N    θ = -18.7

Explanation:

To find the net force, we use Newton's second law, for this we decompose the force using trigonomer

Force 2

    F2 = 61.5 N

   cos 45 = F₂ₓ / F2         F₂ₓ = F2 cos 45

   sin 45 = F₂_y / F2          F₂_y = F2 sin 45

     

force 3

     F3 = 171 N

     cos 45 = F₃ₓ / F3

     sin 45 = F₃_y / F3

the total force can be found with its components

axis x direction (East-West)

      Fₓ = 64.7 +61.5 cos 45 + 171 cos 45

      Fₓ = 229.1 N

Y axis (direction North -Sur)

     F_y = 61.5 sin 45 - 171 sin 45

     F_y = - 77,428 N

the resulting force is

      F = Fx i ^ + Fy j ^

      F = (229.1 i⁻ 77,428 j⁾ N

we can use the Pythagorean theorem to find the module

       F = √ (229.1 2 + 77,428 2)

       F = 241.8 N

let's use trigonometry to find the direction

     tan θ = F_y / Fₓ

     θ = tan⁻¹ (F_y / Fₓ)

     θ = tan⁻¹ (-77,428 / 229.1)

     θ = -18.7

4 0
2 years ago
Net force and direction answer
Contact [7]

Answer:

7. Net force: 14 N

Direction: Right

8. Net force: 360 N

Direction: Right

Explanation:

For Nm 7 the most force is on the right side so it has more power then left side and so its gonna pull towards the right side cancelling the force on the left. So it becomes 26-12 N = 14N

For Nm 8 all the force is on the right side so they add up.

5 0
2 years ago
A proton is trapped in a one-dimensional well that is 200 pm wide. What is the ground state energy of the proton, if the potenti
Harrizon [31]

Answer:

E=1.50\times 10^{-18}J

Explanation:

Energy of the one dimensional infinite well,

E=\frac{n^{2}h^{2} }{8mL^{2} }

Given that, L=200 pm\\L=200\times 10^{-12}m

For the ground state n=1,

Therefore energy is,

E=\frac{(6.626\times 10^{-34})^{2}}{8(9.1\times 10^{-31})(200\times 10^{-12}) ^{2} }\\E=1.50\times 10^{-18}J

8 0
3 years ago
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