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laiz [17]
3 years ago
11

The picture below shows a wheelbarrow. Using a wheelbarrow can make it easier to lift a heavy object by

Physics
1 answer:
timofeeve [1]3 years ago
8 0

Answer:

B IS CORRECT

Explanation:

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The distance a toy car travels over time is shown in the graph.
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Explanation:what’s the answer ?

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What is the difference between the parts of the plot with positive slope and the parts with negative slope?
zalisa [80]

The difference between the parts of the plot with positive slope and the parts with negative slope can be found below.

<h3>What is a slope?</h3>

A slope in a graph is the ratio of the vertical and horizontal distances between two points on a line. Slope shows both steepness and direction of values.

A slope can either be positive or negative depending on the relationship between the variables being plotted.

A positive slope means that the variable are directly related while the negative slope means that two variables are negatively related.

A positive slope further means that the line moves upward when going from left to right on the graph while with the negative slope, the line moves down when going from left to right.

Learn more about slope at: brainly.com/question/2491620

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8 0
2 years ago
A building is being knocked down with a wrecking ball, which is a big metal sphere that swings on a 15-m-long cable. You are (un
Charra [1.4K]

Answer:

1.9 s

Explanation:

We are given that

Length of cable=l=15 m

We have to find the time you have to move out of the way.

We know that

Time period,T=2\pi\sqrt{\frac{l}{g}}

Where g=9.8m/s^2

By using the formula

T=2\pi\sqrt{\frac{15}{9.8}}

T=2\times 3.14\times \sqrt{\frac{15}{9.8}}=7.77 s

Time you have to move out

t=\frac{T}{4}=\frac{7.77}{4}=1.9 s

Hence,time you have to move out of the way=7.77 s

6 0
3 years ago
Q7) A box sliding with a velocity of 5 m/s accelerates at 2 m/s^2. How
grigory [225]

Answer:

The box displacement after 6 seconds is 66 meters.

Explanation:

Let suppose that velocity given in statement represents the initial velocity of the box and, likewise, the box accelerates at constant rate. Then, the displacement of the object (\Delta s), in meters, can be determined by the following expression:

\Delta s = v_{o}\cdot t+\frac{1}{2}\cdot a\cdot t^{2} (1)

Where:

v_{o} - Initial velocity, in meters per second.

t - Time, in seconds.

a - Acceleration, in meters per square second.

If we know that v_{o} = 5\,\frac{m}{s}, t = 6\,s and a = 2\,\frac{m}{s^{2}}, then the box displacement after 6 seconds is:

\Delta s = 66\,m

The box displacement after 6 seconds is 66 meters.

5 0
3 years ago
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