1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
postnew [5]
3 years ago
11

An unstable atomic nucleus has a mass of 17.010-27kg, and starts out at rest. When it decays, it the original nucleus disintegra

tes into three particles. One particle has a mass of 5.0010-27kg and velocity of 6.00106 jm/s, and a second particle has a mass of 8.4010-27kg and velocity of 4.00106 im/s. Calculate (a) the velocity of the third particle and (b) the total increase in kinetic energy as a result of the decay. (Note that this kinetic energy actually comes from the mass of the original nucleus, according to E = ∆mc2, but only a tiny amount of mass is turned into energy, so we don’t have to worry about it for this problem.)
Physics
1 answer:
slega [8]3 years ago
8 0

Answer:

Part a)

v = -(8.33\hat j + 9.33\hat i)\times 10^6 m/s

Part b)

E = 4.4 \times 10^{-13} J

Explanation:

As per momentum conservation we know that there is no external force on this system so initial and final momentum must be same

So we will have

m_1v_1 + m_2v_2 + m_3v_3 = 0

(5 \times 10^{-27})(6 \times 10^6\hat j) + (8.4 \times 10^{-27})(4 \times 10^6\hat i) + (3.6 \times 10^{-27}) v = 0

(30\hat j + 33.6\hat i)\times 10^6 + 3.6 v = 0

v = -(8.33\hat j + 9.33\hat i)\times 10^6 m/s

Part b)

By equation of kinetic energy we have

E = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2 + \frac{1}{2}m_3v_3^2

E = \frac{1}{2}(5 \times 10^{-27})(6\times 10^6)^2 + \frac{1}{2}(8.4 \times 10^{-27})(4 \times 10^6)^2 + \frac{1}{2}(3.6 \times 10^{-27})(8.33^2 + 9.33^2) \times 10^{12}

E = 9\times 10^{-14} + 6.72 \times 10^{-14} + 2.82\times 10^{-13}

E = 4.4 \times 10^{-13} J

You might be interested in
What part of a thunderstorm kills the most people each year?
alexandr1967 [171]
Here is the answer. The part of a thunderstorm that kills the <span> most people each year is the LIGHTNING. Thunder is only the sound created and will not hurt anyone, but it is the lightning that can kill anyone who will be struck by it. Hope this answers your question. Have a great day!</span>
5 0
3 years ago
Read 2 more answers
Water is drawn from a well in a bucket tied to the end of a rope whose other end wraps around a solid cylinder of mass 50 kg and
sleet_krkn [62]

Answer:

\alpha=78.4\ rad.s^{-2}

Explanation:

Given:

  • mass of solid cylinder, m=50\ kg
  • diameter of cylinder, d=0.25\ m
  • mass of bucket of water, m_w=20\ kg

<em>When the bucket is released to fall in the well, it fall under the acceleration due to gravity.</em>

We have formula for angular acceleration as:

\alpha=\frac{g}{r}

where:

g = acceleration due to gravity

r = radius of the cylinder

\aplha=\frac{9.8}{0.125}

\alpha=78.4\ rad.s^{-2}

4 0
3 years ago
1. What happens when like charges come together?*
12345 [234]

Answer:

When like charges come together, they repel each other. For instance, when the north and south poles of a magnet come together, they push each other apart. The like poles in the magnet repel each other and unlike poles attract each other much. The same reaction occurs in like and unlike charges. Also, the repulsion acts along the line between the two charges.

4 0
3 years ago
What is the difference in PE
Blababa [14]

Answer:

831.4 J

Explanation:

Info given:

mass adult: 82.5kg

mass child: 14.7kg

height of wall: 1.25m

g = 9.81m/s^2

PE = mgh

For adult:

mgh = (82.5kg)(9.81m/s^2)(1.25m) = 1011.65 J

For child:

mgh = (14.7kg)(9.81m/s^2)(1.25m) = 180.25 J

Difference in PE: 1011.65 J - 180.25 J = 831.4 J

3 0
2 years ago
Estimate the length of the neptunian year using the fact that the earth is 1.50Ã108km from the sun on average.
Ksenya-84 [330]

Answer:

Explanation:

We know that,

Neptune is 4.5×10^9 km from the sun

And given that,

Earth is 1.5×10^8km from sun

Then,

Let P be the orbital period and

Let a be the semi-major axis

Using Keplers third law

Then, the relation between the orbital period and the semi major axis is

P² ∝ a³

Then,

P² = ka³

P²/a³ = k

So,

P(earth)²/a(earth)³ = P(neptune)² / a(neptune)³

Period of earth P(earth) =1year

Semi major axis of earth is

a(earth) = 1.5×10^8km

The semi major axis of Neptune is

a (Neptune) = 4.5×10^9km

So,

P(E)²/a(E)³ = P(N)² / a(N)³

1² / (1.5×10^8)³ = P(N)² / (4.5×10^9)³

Cross multiply

P(N)² = (4.5×10^9)³ / (1.5×10^8)³

P(N)² = 27000

P(N) =√27000

P(N) = 164.32years

The period of Neptune is 164.32years

6 0
3 years ago
Other questions:
  • A toy train moves 40m in 20s at the constant velocity. What is the toy’s velocity? *<br> 1 point
    7·1 answer
  • If the amplitude of a sound increases, which statement is true
    14·2 answers
  • TRUE OR FALSE: with time and pressure, peat turns into lignite, or brown coal.
    13·2 answers
  • Radio communications were severely Distributed last week And the local newspaper says that solar activity is to blame . Which ty
    5·1 answer
  • What is the speed of a proton after being accelerated from rest through a 5.7×107 v potential difference? express your answer us
    15·1 answer
  • What is meant by the statement "Motion is relativel"?
    14·1 answer
  • An object is placed on a surface. A student tries to apply various combinations of forces on the object. Which pair of forces wi
    14·1 answer
  • Which of the following is an example of acceleration?
    14·2 answers
  • ) It is necessary to maintain a constant fluid volume in the body. Therefore, the body adjusts the water outputs to be equal to
    8·1 answer
  • How will sunlight most likely affect a black shirt on a hot summer day? the temperature of the shirt will depend on how much sun
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!