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musickatia [10]
3 years ago
14

A scientist adds different amounts of salt to 5 bottles of water. He then measures how long it takes for the water to boil. what

is the dependent variable in this experiment?
Physics
1 answer:
g100num [7]3 years ago
4 0
The dependent variable is the amount of time it takes for the water to boil. This variable is dependent because is depends on the amount of salt.
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Various types of tree sloths share the honor of being the slowest moving mammals. An average tree sloth moves at a speed of 0.74
WARRIOR [948]
22.30/0.743 = 30.013 seconds.
3 0
3 years ago
How much heat is needed to raise the temperature of an empty 2.0 x 101 kg vat made of
scZoUnD [109]

Answer:

Q = 7272 Kilojoules.

Explanation:

<u>Given the following data;</u>

Mass = 2.0*101kg = 202kg

Initial temperature, T1 = 10°C

Final temperature, T2 = 90°C

We know that the specific heat capacity of iron = 450J/kg°C

*To find the quantity of heat*

Heat capacity is given by the formula;

Q = mcdt

Where;

  • Q represents the heat capacity or quantity of heat.
  • m represents the mass of an object.
  • c represents the specific heat capacity of water.
  • dt represents the change in temperature.

dt = T2 - T1

dt = 90 - 10

dt = 80°C

Substituting the values into the equation, we have;

Q = 202*450*80

Q = 7272KJ or 7272000 Joules.

6 0
3 years ago
A baseball 0.145kg is thrown vertically upwards with an initial velocity of 20m/s. Use the law of conservation of energy to find
kvasek [131]

Answer: 20.4m

Explanation:

Mass = 0.145kg

Initial velocity, Vi =20m/s

Initial kinetic energy K =1/2mv^2

Initial potential energy Ui = mgx = 0joules

: From conservation of energy,

Uf + Kf = Ui + Ki ( where f represent (final) )

Thus

mgXf + 0 = 0+1/2 mv^2

Xf = Vi^2/ 2g

= (20m/s) ^2/ 2(9.81m/s)^2

=20.4m

5 0
3 years ago
A 1.0 meter long rod is held horizontally in the east-west direction on a distant planet and is dropped from a height of 1.23 m.
enyata [817]

Answer:

The induced emf between two end is 34.02 \times 10^{-5} V

Explanation:

Given:

Length of rod l = 1 m

Height h = 1.23 m

Magnetic field B = 6.93 \times 10^{-5} T

For finding induced emf,

  \epsilon = Blv

Where v = velocity of rod,

For finding the velocity of rod.

From kinematics equation,

 v^{2} = v_{o} ^{2} + 2gh

Where v_{o} = initial velocity, g = 9.8 \frac{m}{s^{2} }

   v = \sqrt{2gh}

   v = \sqrt{2 \times 9.8 \times 1.23}

   v = 4.91 \frac{m}{s}

Put the velocity in above equation,

   \epsilon = 6.93 \times 10^{-5} \times 1 \times 4.91

   \epsilon = 34.02 \times 10^{-5} V

Therefore, the induced emf between two end is 34.02 \times 10^{-5} V

6 0
3 years ago
A 4.0-kg falcon catches a 1.0-kg dove from behind in midair. What is their velocity after impact if the falcon’s velocity is ini
Grace [21]

Answer:

V = 2.8 m/s

Explanation:

It is given that,

Mass of falcon, m_1=4\ kg

Mass of dove, m_2=1\ kg

Initial velocity of falcon, u_1=3\ m/s

Initial velocity of dove, u_2=2\ m/s

When the falcon catches the dove, the momentum remains conserved. Using the formula for the conservation of momentum as :

m_1u_1+m_2u_2=(m_1+m_2)V

V is the velocity after impact

V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

V=\dfrac{4\times 3+1\times 2}{(4+1)}

V = 2.8 m/s

So, their velocity after the impact is 2.8 m/s. Hence, this is the required solution.

7 0
3 years ago
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