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AnnyKZ [126]
3 years ago
14

A bowling ball has a mass of 50 kg and is traveling with a velocity of 18 m/s 4 points

Physics
1 answer:
IRISSAK [1]3 years ago
4 0

momentum= mass × velocity

p= 50×18

momentum= 900 kg m/s

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How could you write an equation for average velocity that would work for finding the average velocity of any object?
melomori [17]
<span>We can define average velocity as,
"the total distance displacement of an object divided by total time taken."

We can say that an object has had displacement if its final position is different from its initial position. Therefore, the formula becomes:

average velocity = total displacement / total time

Keep in mind that displacement is a vector quantity, so it is possible for an object to have covered a distance but if its starting and final positions are the same, then it has had no displacement.</span>
5 0
4 years ago
Electromagnetic waves polarized in the x direction propagate towards an ideal polarizer whose axis is aligned with the y-axis. H
Digiron [165]

Answer:

there is ZERO TRANSMISSION  through the polarizer.

Explanation:

Given the data in the question;

waves was polarized in the x direction propagate towards an ideal polarizer whose axis is aligned with the y-axis.

so θ = 90° { aligned with the y-axis }

now, we know that for polarized light going at angle θ to the polarizer;

I = I₀ × cos²θ

Where I₀ is the intensity of unpolarized light.

I is the intensity after polarization.

so we substitute the value of θ

I = I₀ × cos²( 90° )

I = I₀ × 0

I = 0

Therefore, there is ZERO TRANSMISSION  through the polarizer.

6 0
3 years ago
Why do you think you need to heat the water before adding the sugar?
klemol [59]

Answer:

ig so it's already heated

5 0
3 years ago
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Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 4.50 m above
Virty [35]

8.98×10^6\:\text{m}

Explanation:

First we need to find the acceleration due to gravity on the planet. The wrench took 0.809 s to fall from a height of 4.50 m so we can use the equation

y = -\frac{1}{2}gt^2

Solving for g, we get

g = -\dfrac{2y}{t^2} = -\dfrac{2(-4.50\:\text{m})}{(0.809\:\text{s})} = 13.8\:\text{m/s}^2

Recall that the acceleration due to gravity on a planet's surface can be written as

g = G\dfrac{M_p}{R_p^2}

We can express the mass of the planet M_p in terms of its density \rho as follows:

M_p = \rho \left(\dfrac{4\pi}{3}R_p^3\right) = \dfrac{4\pi}{3}\rho R_p^3

The expression for g then becomes

g = \dfrac{G}{R_p^2} \left(\dfrac{4\pi}{3}\rho R_p^3\right) = \dfrac{4\pi G}{3}\rho R_p

Solving for R_p, we get

R_p = \dfrac{3g}{4\pi G\rho}

\:\:\:\:\:\:\:= \left[\dfrac{3(13.8\:\text{m/s}^2)}{4\pi (6.674×10^{-11}\:\text{Nm}^2\text{/kg}^2)(5500\:\text{kg/m}^3)}\right]

\:\:\:\:\:\:\:= 8.98×10^6\:\text{m}

3 0
3 years ago
Question:
valkas [14]

Answer:

the answer is true.

Explanation:

hope it will help you

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3 years ago
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