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GrogVix [38]
3 years ago
13

Assume you are a perfect blackbody at a temperature of T = 310 K. What is the rate, in watts, at which you radiate energy? (For

the purposes of this problem, you may assume you are spherical with a mass of 70 kg and density equal to that of water)
Physics
1 answer:
madreJ [45]3 years ago
7 0

Answer:

P = 942.54 W

Explanation:

Given:

Temperature, T = 310 K

mass, m = 70 kg

Now from the stefan's law,

we have the formula

P = σAT⁴

where,

P = radiate energy

σ = Stefan's constant = 5.67 × 10⁻⁸ W/(m² K⁴)

A = Area of the body

Average surface area for a human body = 1.8 m²

T = Temperature

on substituting the values we get,

P = 5.67 × 10⁻⁸ × 1.8 × 310⁴

or

P = 942.54 W

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The pressure drop in pascal is 3.824*10^4 Pascals.

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