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3 years ago

11

G varies directly with h and inversely with the square off. When h=16,f=2,

1 answer:

Rufina [12.5K]3 years ago

6 0

Answer:

wefew

Step-by-step explanation:

awhefiuLLLESoagFVRESESGREGESRGSAERG$W$EG$%agwafer

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What is the value of c in the equation y = 4x^2 -10x + c if the y-coordinate of the vertex is -7

love history [14]

Answer: $c=-\frac{3}{4}$

Step-by-step explanation:

Find the x-coordinate of the vertex with this formula:

$x=\frac{-b}{2a}$

In this case:

$a=4\\b=-10$

Substituting values, we get:

$x=\frac{-(-10)}{2(4)}=\frac{5}{4}$

Now we can substitute the coordinates of the vertex into the equation $y = 4x^2 -10x + c$ and then solve for "c".

Then:

$-7 = 4(\frac{5}{4})^2 -10(\frac{5}{4}) + c\\\\-7+\frac{25}{4}=c\\\\c=-\frac{3}{4}$

6 0

3 years ago

2.4 Assignment 4

brilliants [131]

Answer:

Step-by-step explanation:

8 0

2 years ago

PLEASE SHOW ALL WORK I WILL GIVE BRAINLY THIS IS DUE IN 5 MINS PLEASE HELP ME

goldfiish [28.3K]

35/100= x/80 x=28 8/100=x/5 x=0.4 50/100=x/125 x=62.5 12/100=48/x x=400

3 0

2 years ago

Charity invests $1891 into a savings account. The account will accrue 9% interest to be compounded semiannually. Provided she ma

Norma-Jean [14]

Answer:

B) 12,010.9

Step-by-step explanation:

Set up an equation:

$A=1891(1+\frac{0.09}{2})^{2*21}$

Solve:

$A=1891(1.045)^{42}$

$A=12010.90488$

8 0

2 years ago

Answer the question above

Vera_Pavlovna [14]

Answer:

$tan\:\left(\frac{5\pi }{6}\right)=tan\left(-\frac{\pi }{6}\right)$

Option A is correct.

Step-by-step explanation:

We need to find equivalent of $tan\:\left(\frac{5\pi }{6}\right)$

First we solve $tan\:\left(\frac{5\pi }{6}\right)$

We get $-\frac{1}{\sqrt{3} }$

Now checking all the options.

Option A: $tan\:(-\frac{\pi}{6} )$

Solving $tan\left(-\frac{\pi }{6}\right)\: we\: get\: \mathbf{ -\frac{1}{\sqrt{3} }}$

Option B: $tan\left(\frac{7\pi }{6}\right)$

Solving $tan\left(\frac{7\pi }{6}\right)\: we\: get\: \mathbf{\frac{1}{\sqrt{3} }}$

Option C: $cot\left(\frac{5\pi }{6}\right)$

Solving $cot\left(\frac{5\pi }{6}\right)\:we\:get\:\mathbf{-\sqrt{3} }$

Option D : $tan\left(-\frac{5\pi }{6}\right)$

Solving $tan\left(-\frac{5\pi }{6}\right) \:we\:get:\mathbf{\frac{1}{\sqrt{3} } }$

So, looking at the options, only Option A has the same result as given question

So, $tan\:\left(\frac{5\pi }{6}\right)=tan\left(-\frac{\pi }{6}\right)$

Option A is correct.

3 0

2 years ago