we have a maximum at t = 0, where the maximum is y = 30.
We have a minimum at t = -1 and t = 1, where the minimum is y = 20.
<h3>
How to find the maximums and minimums?</h3>
These are given by the zeros of the first derivation.
In this case, the function is:
w(t) = 10t^4 - 20t^2 + 30.
The first derivation is:
w'(t) = 4*10t^3 - 2*20t
w'(t) = 40t^3 - 40t
The zeros are:
0 = 40t^3 - 40t
We can rewrite this as:
0 = t*(40t^2 - 40)
So one zero is at t = 0, the other two are given by:
0 = 40t^2 - 40
40/40 = t^2
±√1 = ±1 = t
So we have 3 roots:
t = -1, 0, 1
We can just evaluate the function in these 3 values to see which ones are maximums and minimums.
w(-1) = 10*(-1)^4 - 20*(-1)^2 + 30 = 10 - 20 + 30 = 20
w(0) = 10*0^4 - 20*0^2 + 30 = 30
w(1) = 10*(1)^4 - 20*(1)^2 + 30 = 20
So we have a maximum at x = 0, where the maximum is y = 30.
We have a minimum at x = -1 and x = 1, where the minimum is y = 20.
If you want to learn more about maximization, you can read:
brainly.com/question/19819849
In slope intercept form its, y=2x-2
Answer:
224
Step-by-step explanation:
Number of trains in the roller coaster = 2
Number cars in each train = 7
Total number of cars = Number of trains 
Number of cars in each train = 
= 14
Number of people in each car = 16
Total number of people in 14 cars = Number of people in one car Number of cars = 16 14 = 224
i.e.
Total number of people in the roller coaster in one run = 224
Number of runs made by each train in one hour = 10
Therefore, Total number of people that can ride the roller coaster in one hour can be found by multiplying the number of runs with total number of people in the roller coaster in one run.
224 10 = <em>2240</em>
How can I send you the drawn representation on number line ?
25)
z + 4 >= 2z
-z >= -4
z <= 4 (you flip the sign when you divide over negative number)
on number line: from 4 to -infinity
you use normal arithmetic like equations
29)
-9 + 2a < 3a
-9 < a (just one step done)
on number line from -9 to infinity
41 and 43 ? not in the page
