Answer:
All figures in Group 1 appear to have at
least one square face
Step-by-step explanation:
Let us examine each statement and see whether they are true or not.
The first statement is not true. Only one of the figures (square pyramid) has at least one triangular face. It has 4 triangular faces, actually.
The second statement is not true. Only one of the figures is a rectangular prism. The remaining two are triangular pyramid and triangular prism respectively.
The third statement is not true also. Only 1 figure is a triangular prism.
The fourth statement is correct. In group 1, all the figures has at least one square face.
Answer:
A) 3π/4
B) 9π/7
C) 11π/6
Step-by-step explanation:
In the picture attached, the points are shown
Point A is between π/2 radians (90°) and π radians (180°). The only possible option is 3π/4
Point B is between π radians (180°) and 3π/2 radians (270°). The only possible option is 9π/7
Point C is between 3π/2 radians (270°) and 2π radians (360°). The only possible option is 11π/6
Answer: 34/10=3.4 The estimated quotient is 3.4
Step-by-step explanation: Basically, you are dividing 33.7 by 9.5, but first you will need to round to the nearest whole number. A whole number does not contain a decimal. 33.7 rounded to the nearest whole number is 34. 9.5 rounded to the nearest whole number is 10. So, you are dividing 34 by 10. 34 divided by 10 is 3.4.
Answer:
680
Step-by-step explanation:
Ratio of red to white 4 : 7
Number of white = 280
White + red buttons = x
7x / 11 = 280
7x = 280 * 11
7x = 3080
x = 3080 / 7
x = 440
Number of red buttons 440 - 280 = 160
Number of red bottons ;
Blue + red buttons = x
3 : 2 ; blue : red
3 + 2 = 5 ;
2x / 5 = 160
2x = 160 * 5
2x = 800
x = 800 / 2
x = 400
Number of Blue buttons :
400 - 160 = 240
Total :
White + red + blue
280 + 160 + 240 = 680 buttons
Answer:
7x⁴ + 5x³ + 7x² + 6x + 5
Step-by-step explanation:
The given expression is
(5x4 + 5x3 + 4x - 9) + (2x4 + 7x2 + 2x + 14)
The first step is to open the brackets by multiplying each term inside each bracket by the term outside each bracket. Since the term outside each bracket is 1, the expression becomes
5x⁴ + 5x³ + 4x - 9 + 2x⁴ + 7x² + 2x + 14
We would collect like terms by combining each term with the same exponent or raised to the same power. The term would be arranged in decreasing order of the exponents. It becomes
5x⁴ + 2x⁴ + 5x³ + 7x² + 4x + 2x - 9 + 14
7x⁴ + 5x³ + 7x² + 6x + 5
