Answer:
organisms that have more favorable traits tend to leave more offspring ... improved fitness of certain individuals in the population that allows for survival and reproduction. ... Based on H-W conditions, five major causes of evolution: ... factors that prevent organisms of two species from producing vigorous, fertile offspring
Explanation:
Im not sure but if there was a graph maybe
I think the correct answer from the choices listed above would be the second option. In multicell organisms, cells that work together to perform a certain function form <span>Organs. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>
At the place marked with the letter A we have a divergent plate boundary. On this type of boundary, the plates are moving away from one another. As they move away, they leave a gap behind them, and the crust is becoming thinner and thinner with lots of cracks in it. Because of that, the high pressures from the mantle manage to push upwards the magma with ease. The magma reaches the seafloor and it is pushing the crust upwards until it breaks it. As the magma pushes the crust upwards,underwater volcanoes are formed, and when the crust is broken by the magma, the magma flows get on the seafloor, cool of very quickly in the water, and create new crust.
To first dive into your question, here are some vocabulary terms that I will be using and will be helpful to you as well.
- Homozygous dominant (BB): <em>Is not affected by cystic fibrosis</em>.
- Homozygous recessive (bb):<em> Is affected by cystic fibrosis</em>.
- Heterozygous (Bb):<em> A carrier for cystic fibrosis</em>.
- Phenotype (Ex: Having cystic fibrosis): <em>The appearance of an allele pair</em>.
- Genotype (Ex: bb): <em>The genetic makeup of an allele pair</em>.
We know that if both of the parents are phenotypically normal, there is no way that they can be homozygous recessive (bb), or have cystic fibrosis. We also know that since they have a child with this disease, they can't be homozygous dominant (BB) either. This means that <u>both parents have to be carriers (Bb)</u> in order for them to have a child with cystic fibrosis.
Below I have attached a Punnett square with both of the heterozygous parents.
<em>Each child they have will have a </em><u><em>1/4</em></u><em> or </em><u><em>25%</em></u><em> chance of having cystic fibrosis.</em>