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monitta
3 years ago
14

Identify the asymptotes of y=1 over x -6 A. B. C. D.

Mathematics
1 answer:
Westkost [7]3 years ago
6 0

Answer:

  D.  x = 0; y = -6

Step-by-step explanation:

There is a vertical asymptote at the value of x that makes the denominator zero. That value is x=0. This is sufficient to choose the correct answer.

When x gets large, the term 1/x nears zero, so the value of y nears -6. This is the horizontal asymptote.

  vertical asymptote: x = 0; horizontal asymptote: y = -6

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avanturin [10]

Answer:

y = 41

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Step-by-step explanation:

8 0
3 years ago
The sum of a number (n) and 14 is 72 which equation shows this relationship
iren [92.7K]
" the sum " means add

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8 0
3 years ago
Read 2 more answers
Help? I don't get it. If you could show the process tha'd be great! :)
Vaselesa [24]
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3 0
3 years ago
Find the value of cos θ if the angle θ is in the third quadrant and sinθ= -0.8
Rudiy27

Correct option is D) -0.6.

<u>Step-by-step explanation:</u>

We have sin\alpha  = -0.8 . Also, we know that cos\alpha  = \sqrt{1- (sin\alpha } )^{2} . Let's find out value of cos\alpha  using above formula:

cos\alpha  = \sqrt{1- (sin\alpha } )^{2}

⇒ cos\alpha  = \sqrt{1- (sin\alpha } )^{2}

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3 0
3 years ago
Help please Thanks - Celgio111
slega [8]
Whatever decimals you choose, b HAS to be greater than a. It can't be the other way around where a is greater. So a possible answer could be, b=0.9 and a=0.3 
7 0
3 years ago
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