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Alex
3 years ago
10

P = 3. Q = -2. Solve 4PQ

Mathematics
2 answers:
SashulF [63]3 years ago
7 0

Answer:

-24

Step-by-step explanation:

4(3)(-2) = -24

gtnhenbr [62]3 years ago
6 0
4(3)(-2)
=12(-2)
=-24
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DiKsa [7]
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3 years ago
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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
astra-53 [7]

Answer:

3\pi \rightarrow y=2\cos \dfrac{2x}{3}\\ \\\dfrac{2\pi }{3}\rightarrow y=6\sin 3x\\ \\\dfrac{\pi }{3}\rightarrow  y=-3\tan 3x\\ \\10\pi \rightarrow y=-\dfrac{2}{3}\sec \dfrac{x}{5}

Step-by-step explanation:

The period of the functions y=a\cos(bx+c) , y=a\sin(bx+c), y=a\sec (bx+c) or y=a\csc(bx+c) can be calculated as

T=\dfrac{2\pi}{b}

The period of the functions y=a\tan(bx+c) or y=a\cot(bx+c) can be calculated as

T=\dfrac{\pi}{b}

A. The period of the function y=-3\tan 3x is

T=\dfrac{\pi}{3}

B. The period of the function y=6\sin 3x is

T=\dfrac{2\pi}{3}

C. The period of the function y=-4\cot \dfrac{x}{4} is

T=\dfrac{\pi}{\frac{1}{4}}=4\pi

D. The period of the function y=2\cos \dfrac{2x}{3} is

T=\dfrac{2\pi}{\frac{2}{3}}=3\pi

E. The period of the function y=-\dfrac{2}{3}\sec \dfrac{x}{5} is

T=\dfrac{2\pi}{\frac{1}{5}}=10\pi

5 0
3 years ago
Help. help.!!!!!!!!!!!!!!!!!!
Shkiper50 [21]

Answer:

2

Step-by-step explanation:

7 0
3 years ago
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3 years ago
3x - 2y &gt; 12<br> Please I need as soon as possible
Novosadov [1.4K]

Answer:

y<-6+3x/2

Step-by-step explanation:

6 0
3 years ago
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