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Gwar [14]
3 years ago
15

We have x = 7 so now solve for y by replacing x with 7 in this equation 2x + y = 20

Mathematics
2 answers:
Ivahew [28]3 years ago
7 0

Answer:

y=6

Step-by-step explanation:

2(7)=14.

subtract both sides by 14.

y=6

Pachacha [2.7K]3 years ago
6 0

Answer:

y = 6

Step-by-step explanation:

x=7 , 2x+y=20

2(7)+y=20

14+y=20

14-14+y=20-14

y = 6

hope it's helpful ❤❤❤❤❤❤

THANK YOU.

#

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A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is normally distributed with σ=0.0
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<h2>Answer with explanation:</h2>

The confidence interval for population mean is given by :-

\overline{x}\pm z^* SE                   (1)

, where \overline{x} = sample mean

z* = critical value.

SE = standard error

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n= sample size.

As per given , we have

\overline{x}=74.021

\sigma=0.001

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It is known that ring diameter is normally distributed.

SE=\dfrac{0.001}{\sqrt{15}}=0.000258198889747\approx0.000258199

By z-table ,

The critical value for 95% confidence  = z*= 1.96

A 99% two-sided confidence interval on the true mean piston diameter :

74.021\pm (2.576) (0.000258199)     (using (1))

74.021\pm 0.000665120624

74.021\pm 0.000665120624\\\\=(74.021- 0.000665120624,\ 74.021+ 0.000665120624)\\\\=(74.0203348794,\ 74.0216651206)\approx(74.020,\ 74.022)  [Rounded to three decimal places]

∴  A 99% two-sided confidence interval on the true mean piston diameter  = (74.020, 74.022)

By z-table ,

The critical value for 95% confidence  = z*= 1.96

A 95% lower confidence bound on the true mean piston diameter:

74.021- (1.96) (0.000258199)    (using (1))

74.021- 0.00050607004=74.02049393\approx74.020 [Rounded to three decimal places]

∴  A 95% lower confidence bound on the true mean piston diameter= 74.020

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