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Doss [256]
3 years ago
9

A baseball player slides into home base and experiences coefficients of friction of μ8 = 0.63 and μk = 0.49. The normal force ac

ting on the player is 660N. How much frictional force acts on the player?Round your answer to the nearest hundredth if necessary. Ff = ________ N
Physics
1 answer:
hammer [34]3 years ago
8 0

Answer:

323.4 N

Explanation:

Given that,

The coefficient of static friction, \mu_s=0.63

The coefficient of kinetic friction, \mu_k=0.49

We need to find the frictional force acting on the player. As the baseball player is sliding into home base, we will use the coefficient of kinetic friction to find the frictional force.

F=\mu _kN\\\\=0.49\times 660\\\\=323.4\ N

So, the frictional force acting on the player is 323.4 N.

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d = speed x time

distance = 29 x 30

distance = 870m

please mark as BRAINLIEST

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2 years ago
Energy of fossil fuel is also derived from solar energy why​
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Explanation:

All the energy in oil, gas, and coal originally came from the sun captured through photosynthesis. In the same way that we burn wood to release energy that trees capture from the sun, we burn fossil fuels to release the energy that ancient plants captured from the sun.

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3 years ago
a 282 kg bumper car moving right at 3.50 m/s collides with a 155 kg bumper car moving 1.88 m/s left. afterwards, the 282 kg car
Vaselesa [24]

The momentum of the 155 kg car afterwards is 469.7 kg m/s to the right

Explanation:

We can solve the problem by using the law of conservation of momentum: the total momentum of the system is conserved before and after the collision, so we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where:

m_1 = 282 kg is the mass of the bumper car

u_1 = 3.50 m/s is the initial velocity of the bumper car (we take the right as positive direction)

v_1 = 0.800 m/s is the final velocity of the bumper car

m_2 = 155 kg is the mass of the second bumper car

u_2 = -1.88 m/s is the initial velocity of the second car (moving to the left)

v_2 is the final velocity of the second car

Solving for v_2,

v_2 = \frac{m_1 u_1+m_2 u_2 - m_1 v_1}{m_2}=\frac{(282)(3.50)+(155)(-1.88)-(282)(0.800)}{155}=3.03 m/s

where the positive sign means the direction is to the right.

And now we can find the momentum of the 155 kg afterwards, which is

p_2 = m_2 v_2 = (155)(3.03)=469.7 kg m/s (to the right)

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3 years ago
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earnstyle [38]

Answer:

Technician A

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A tire with a lower aspect ratio responds to lateral force more effectively than a tire with a higher aspect ratio. The aspect ratio affects steering stability. Generally, the shorter the sidewall, or the lower the aspect ratio, the less time it takes to transmit the steering input from the wheel to the tread. The result is quicker steering response. Aspect ratio also affects the tread contact patch. As a rule, a low-profile tire produces a wider tread contact patch. This wider tread contact patch creates a stiffer footprint that reduces distortion and provides improved cornering traction. Aspect ratio also impacts ride. A low-profile tire usually has a stiffer ride than the standard aspect ratio of 75 or more.

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4 years ago
What is the difference between newtons law of gravitation and Coulombs law?​
svlad2 [7]
Coulomb's law explains the force between the charges whereas Newton's law of gravitation explains the force between the masses. ... The electrostatic force may be positive or negative in the case of Coulomb's law but the force is always negative in the case of Newton's law of gravitation
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