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ArbitrLikvidat [17]
4 years ago
13

A flat screen is located 0.63 m away from a single slit. Light with a wavelength of 550 nm (in vacuum) shines through the slit a

nd produces a diffraction pattern. The width of the central bright fringe on the screen is 0.053 m. What is the width of the slit?
Physics
1 answer:
s2008m [1.1K]4 years ago
5 0

Answer:

1.308 * 10^(-5) m

Explanation:

We apply the condition for a single slit experiment:

y = (λ * D) / a

Where y = half width of fringe

λ = wavelength of light

D = distance of slit from screen

a = width of slit

We need to find a, so we make a the subject of formula:

a = (λ * D) / y

From the question:

λ = 550 nm = 550 * 10^(-9) m

D = 0.63 m

y = 0.053 / 2 = 0.0265 m

Therefore:

a = (550 * 10^(-9) * 0.63) / 0.0265

a = 1.308 * 10^(-5) m

The width of the slit is 1.308 * 10^(-5) m

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An astronaut is in equilibrium when he is positioned 140 km from the center of asteroid C and 581 km from the center of asteroid
serg [7]

Answer:B

Explanation:

Given

Distance of astronaut From asteroid x is r_x=140 km

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If the astronaut is in equilibrium then net gravitational force on it is zero

F_x=F_y

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\frac{M_x}{M_y}=(\frac{140}{581})^2

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8 0
3 years ago
Help please!
JulsSmile [24]

3. The sum of the players' momenta is equal to the momentum of the players when they're stuck together:

(75 kg) (6 m/s) + (80 kg) (-4 m/s) = (75 kg + 80 kg) v

where v is the velocity of the combined players. Solve for v :

450 kg•m/s - 320 kg•m/s = (155 kg) v

v = (130 kg•m/s) / (155 kg)

v ≈ 0.84 m/s

4. The total momentum of the bowling balls prior to collision is conserved and is the same after their collision, so that

(6 kg) (5.1 m/s) + (4 kg) (-1.3 m/s) = (6 kg) (1.5 m/s) + (4 kg) v

where v is the new velocity of the 4-kg ball. Solve for v :

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satela [25.4K]

Answer:

Its mechanical energy is the same.

Explanation:

If forces are only conservative, the mechanical energy will be the same.

It can be different if energy get transformed in another kind of energy like elastic energy for example, although the amount of energy is always the same.

If we just have mechanical energy not geting transformed we have:

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