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ArbitrLikvidat [17]
4 years ago
13

A flat screen is located 0.63 m away from a single slit. Light with a wavelength of 550 nm (in vacuum) shines through the slit a

nd produces a diffraction pattern. The width of the central bright fringe on the screen is 0.053 m. What is the width of the slit?
Physics
1 answer:
s2008m [1.1K]4 years ago
5 0

Answer:

1.308 * 10^(-5) m

Explanation:

We apply the condition for a single slit experiment:

y = (λ * D) / a

Where y = half width of fringe

λ = wavelength of light

D = distance of slit from screen

a = width of slit

We need to find a, so we make a the subject of formula:

a = (λ * D) / y

From the question:

λ = 550 nm = 550 * 10^(-9) m

D = 0.63 m

y = 0.053 / 2 = 0.0265 m

Therefore:

a = (550 * 10^(-9) * 0.63) / 0.0265

a = 1.308 * 10^(-5) m

The width of the slit is 1.308 * 10^(-5) m

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An RLC circuit is used in a radio to tune into the radio lagos fm Station broadcasting at 93.5Hz. The resistance is 15ohms and t
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The characteristics of the RLC circuit allow to find the result for the capacitance at a resonance of 93.5 Hz is:

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A series RLC circuit reaches the maximum signal for a specific frequency, called the resonance frequency, this value depends on the impedance of the circuit.

            Z^2 = R^2 + ( wL - \frac{1}{wC} )^2  

Where Z is the impedance of the circuit, R the resistance, L the inductance, C the capacitance and w the angular velocity. The negative sign is due to the fact that the current in the capacitor and the inductor are out of phase.

In the case of resonance, the impedance term completes the circuit as a resistive system.

           wL - \frac{1}{wC} = 0  \\w^2 = \frac{1}{LC}  

           

Indicate that the inductance L = 1.6 H and the frequency f = 93.5 Hz.

Angular velocity and frequency are related.

         

         w = 2π f

           

Let's  substitute.

          C = \frac{1}{L ( 2 \pi f)^2 }  

 

Let's calculate.

         C = \frac{1}{1.6 \ ( 2\pi \ 93.5)^2}  

         C = 1.8 10⁻⁶ F

In conclusion with the characteristics of the RLC circuits we can find the result for the capacitance at a 93.5 Hz resonance is:

  • Capacitance is C = 1.8 10⁻⁶ F

Learn more about serial RLC circuits here: brainly.com/question/15595203

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