10 decreased by twice a
1 answer:
You might be interested in
-22 - x = 5 + 6x + 9 Combine like terms (5 and 9)
-22 - x = 14 + 6x Subtract 6x from both sides
-22 - 7x = 14 Add 22 to both sides
-7x = 36 Divide both sides by -7
x = 5
-22 - x = 14 + 6x Subtract 6x from both sides
-22 - 7x = 14 Add 22 to both sides
-7x = 36 Divide both sides by -7
x = 5
The problem can be solved step by step, if we know certain basic rules of summation. Following rules assume summation limits are identical.
Armed with the above rules, we can split up the summation into simple terms:
=> (a) f(x)=28n-n^2
=> f'(x)=28-2n
=> at f'(x)=0 => x=14
Since f''(x)=-2 <0 therefore f(14) is a maximum
(b) f(x) is a maximum when n=14
(c) the maximum value of f(x) is f(14)=196
Armed with the above rules, we can split up the summation into simple terms:
=> (a) f(x)=28n-n^2
=> f'(x)=28-2n
=> at f'(x)=0 => x=14
Since f''(x)=-2 <0 therefore f(14) is a maximum
(b) f(x) is a maximum when n=14
(c) the maximum value of f(x) is f(14)=196