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valkas [14]
2 years ago
6

Zach has a basic cell phone plan that does not include texting. He is going to add a texting package to his cell phone plan. He

has two choices of texting packages, A and B. Package A charges $0.15 per text with no monthly fees for the texting package. Package B charges $0.10 per text, but has a $10 monthly fee for the texting package. Write an equation that represents the total cost for each texting package if any amount of texts are sent. Be sure to define the variables you are using for your equation.
Mathematics
2 answers:
sertanlavr [38]2 years ago
8 0

Answer: STUPID

Step-by-step explanation:

Triss [41]2 years ago
4 0

Answer:

bababoeybababoey

Step-by-step explanation:

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The equation of a parabola is y=x^2–4x+13. Write the equation in vertex form.
Korolek [52]

Answer:

y = (x - 2)² + 9

Step-by-step explanation:

To obtain the equation in vertex form use the method of completing the square.

Add/ subtract ( half the coefficient of the x- term)² to x² - 4x

y = x² + 2(- 2)x + 4 - 4 + 13

  = (x - 2)² + 9 ← in vertex form

5 0
2 years ago
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A 20 foot ladder is leaning against a tree. The bottom of the ladder is 12 feet away from the bottom of the tree. Approximately
Nutka1998 [239]
9.2 is the answer and in your case C.
8 0
3 years ago
If one pound of water has a mass of 453.6 grams, what would be the mass of 2.2 pounds of water?
iren2701 [21]
The answer would be 997.92
8 0
3 years ago
A group of volunteers has been collecting toys to deliver to a local charity. Over the last 5 days, the volunteers have collecte
sweet [91]

Answer:

  • Their rate was 85 toys per day.

Step-by-step explanation:

<u>Given equation:</u>

  • 425 ÷ 5

<u>Now, let's solve the equation:</u>

  • 425 ÷ 5
  • = 85

Their rate was 85 toys per day.

3 0
2 years ago
What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
2 years ago
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