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MrRissso [65]
2 years ago
13

Stephen deposited $1800 into a savings account for which interest is compounded weekly at a rate of 3.2%. How much interest will

he earn after 10 years?
A. $58.51

B. $678.59

C. $2478.59

D. $7679.48
Mathematics
1 answer:
Nady [450]2 years ago
8 0
Hi there
First find the future value using the compound interest formula
The formula is
A=p (1+r/k)^kn
A future value?
P present value 1800
R interest rate 0.032
K compounded weekly 52
N time 10 years
A=1,800×(1+0.032÷52)^(52×10)
A=2,478.59

Now find the interest earned
I=A-p
A future value 2478.59
P present value 1800
So
I=2,478.59−1,800
I=678.59

It's b

Good luck!
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11x+16

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Because x+10x=11x.

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you save $5,000.00 and invest 60% of it in stocks while leaving the rest in a savings account earning a 4.9% APR. The stock incr
Nataly_w [17]
Amount invested in stocks
5,000×0.60
=3,000
after one year gains 9%
3,000×(1+0.09)
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3,270×(1−0.04)
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Amount of saving account
5,000×0.40
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After 2 years
2,000×(1+0.049)^(2)
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So it gained 200.802 (2200.802-2000)

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5 0
3 years ago
One spring day, Dylan noted the time of day and the temperature, in degrees
allochka39001 [22]

Answer:

Please find attached the required graph for the temperature time relationship

Step-by-step explanation:

The parameters given are arranged in a tabular form as follows;

At

Time  {}                                          Temperature

6 a. m.        {}                                    56° F

7 a. m.          {}                                   59° F

8 a. m.             {}                                62° F

9 a. m.             {}                                66° F

10 a. m.            {}                               70° F

11 a. m.                  {}                          74° F

12 p. m.              {}                             74°F

1 p. m.                     {}                        74°F

2 p. m.                  {}                          74°F

3 p. m.                   {}                         74°F

4 p. m.                   {}                         74°F

5 p. m.                  {}                          74°F

6 p. m.                 {}                           74°F

7 p. m.                       {}                     71°F

8 p. m.                      {}                      68°F

9 p. m.                          {}                  65°F

10 p. m.                  {}                         62°F

11 p. m.                        {}                    61.5°F

12 a. m.                        {}                    61°F

With the above table as the data points, the graph can be drawn

From Excel, The Mean temperature is approximately 68.1°F

The standard deviation is 6.079 °F

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tiny-mole [99]

Answer:4

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We also know the parabola passes through (-4, 2).

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2 = a − 2

a = 4

So the coefficient of the squared expression is 4.

8 0
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