Answer:
Hence, the relation R is a reflexive, symmetric and transitive relation.
Given :
A be the set of all lines in the plane and R is a relation on set A.

To find :
Which type of relation R on set A.
Explanation :
A relation R on a set A is called reflexive relation if every
then
.
So, the relation R is a reflexive relation because a line always parallels to itself.
A relation R on a set A is called Symmetric relation if
then
for all
.
So, the relation R is a symmetric relation because if a line
is parallel to the line
the always the line
is parallel to the line
.
A relation R on a set A is called transitive relation if
and
then
for all
.
So, the relation R is a transitive relation because if a line
s parallel to the line
and the line
is parallel to the line
then the always line
is parallel to the line
.
Therefore the relation R is a reflexive, symmetric and transitive relation.
18-8=10
10*2.2=22
his dog is 22 lbs above the typical weight
Equation To write :2 {x+ ( x+5) }=30
Let's solve your equation step-by-step.
2(x+x+5)=30
Step 1: Simplify both sides of the equation.
2(x+x+5)=30
(2)(x)+(2)(x)+(2)(5)=30(Distribute)
2x+2x+10=30
(2x+2x)+(10)=30(Combine Like Terms)
4x+10=30
4x+10=30
Step 2: Subtract 10 from both sides.
4x+10−10=30−10
4x=20
Step 3: Divide both sides by 4.
4x
4
=
20
4
x=5
So... x+5=10.
Area =5x10=50 cm squared.
You should have an angle of elevation of 30 degrees.
The answer would be 30 if u use the gcf