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leonid [27]
3 years ago
9

I forgot how to do this if you could help with one that would be great thanks!

Mathematics
1 answer:
Anna35 [415]3 years ago
8 0
If the relationship is parallel, you find the gradient/slope (m) in the equation y=mx+c. Then substitute the point and the gradient/slope into the equation y-y1=m(x-x1), after that you work it out algebraically making y the subject.

Question 1... Line: y=3x+5   Point: (1/3, 4)   Relationship: Parallel
m = 3      y-4=3(x-1/3)
               y-4=3x-1
                  y=3x+3

If the relationship is perpendicular then you find the gradient/slope (m) from the equation y=mx+c, after doing that you sub m into the equation m1*m2= -1 (solve algebraically to make m2 the subject). Then you substitute the answer of m2 and the points into the equation y-y1=m2(x-x1).

Question 5... Line y=-3x+5   Point: (3, 2)   Relationship: Perpendicular
m= -3
-3*m2= -1            y-2=1/3(x-3)
     m2= 1/3          y-2=1/3x-1
                               y=1/3x+1

I can send you the photo of the working if you wish, since it's a bit hard to read online.
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DIA [1.3K]

Answer:

y = \frac{3}{2} x + 13

Step-by-step explanation:

1) Use point-slope formula y-y_1 = m (x-x_1) to find the slope-intercept form (or y = mx + b form) of the equation. m represents the slope, and x_1 and y_1 represent the x and y values of a point the line intersects. So, substitute \frac{3}{2} for m, -4 for x_1, and 7 for y_1. Then, simplify and isolate y on the left side like so:

y-(7) = \frac{3}{2} (x - (-4)) \\y -7 = \frac{3}{2} (x + 4) \\y - 7 = \frac{3}{2} x + 6\\y = \frac{3}{2} x + 13

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What is the simplify of this expression -2(2b-3)
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