Hey can someone please help me with this

The function f(x) is graphed below. The domain of the function is

GarryVolchara [31]

Answer:

[-1, infinity)

Step-by-step explanation:

The graphs starts from X=1 and remains defined from X =1 to infinity. The domain of the function is, thus, [-1, infinity)

5 0

3 years ago

Two friends share 76 blueberries. To count the blueberries they put them

Usimov [2.4K]

In there mouth and they ate them

6 0

4 years ago

Find the zero(s) of each function algebraically.<br>f(x) = 8x-16<br>

vodomira [7]

the zero(s) of function $f(x)=8x-16$ is x=2

Step-by-step explanation:

We need to find the zero(s) of function algebraically.

We are given: $f(x)=8x-16$

To find the zeros we put the function equal to zero.

$8x-16=0\\Solving:\\8x=16\\x=\frac{16}{8}\\x=2$

So, the zero(s) of function $f(x)=8x-16$ is x=2

Keywords: zero(s) of function

Learn more about zero(s) of function at:

#learnwithBrainly

4 0

3 years ago

A rectangular storage container with a lid is to have a volume of 2 m3. The length of its base is twice the width. Material for

Scilla [17]

Answer:

Dimensions are 2 m by 1 meter by 1 meter,

Minimum cost is $ 18.

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

Since, the length is twice of the width,

So, length of the container = 2w,

Now, if h be the height of the container,

Volume = length × width × height

2 = 2w × w × h

1 = w² × h

$\implies h=\frac{1}{w^2}$

Since, the area of the base = l × w = 2w × w = 2w²,

Area of the lid = l × w = 2w²,

While the area of the sides = 2hw + 2hl

= 2h( w + l)

$= 2\times \frac{1}{w^2}(w+2w)$

$=\frac{6w}{w^2}$

$=\frac{6}{w}$

Since, Material for the base costs $1 per m². Material for the sides and lid costs $2 per m²,

So, the total cost,

$C(w) = 1\times 2w^2+2\times 2w^2 + 2\times \frac{6}{w}$

$=2w^2+4w^2+\frac{12}{w}$

$=6w^2+\frac{12}{w}$

Differentiating with respect to w,

$C'(w) = 12w -\frac{12}{w^2}$

Again differentiating with respect to w,

$C''(w) = 12 + \frac{24}{w^3}$

For maxima or minima,

C'(w) = 0

$\implies 12w -\frac{12}{w^2}=0$

$\implies 12w^3 - 12=0$

$w^3-1=0\implies w = 1$

For w = 1, C''(w) = positive,

Hence, for width 1 m the cost is minimum,

Therefore, the minimum cost is C(1) = 6(1)²+12 = $ 18,

And, the dimension for which the cost is minimum is,

2 m by 1 meter by 1 meter.

7 0

4 years ago

Find cos ⁡ ( 2 ⋅ ∠ A B C ) cos(2⋅∠ABC)

Pavlova-9 [17]

The value of the cosine function is -0.385

<h3>How to determine the measure of the cosine function?</h3>

The figure that completes the question is added as an attachment

From the figure, we have the following sides

AB = √13

AC = 3

BC = 2

The triangle is a right triangle.

The angle B is calculated as:

cos(B) = 2/√13

Evaluate

cos(B) = 0.5547

Take the arccos of both sides

B = 56.31

This means that:

cos(ABC) = cos(56.31)

Multiply ABC by 2.

So, we have:

cos(ABC * 2) = cos(56.31 * 2)

Evaluate the product

cos(ABC * 2) = cos(112.62)

Evaluate the cosine

cos(ABC * 2) = -0.385

Hence, the value of the cosine function is -0.385