Answer : The concentration of is, 0.12 M
Explanation :
Using Henry's law :
where,
= concentration of
= ?
= partial pressure of
= 4.5 atm
= Henry's law constant =
Now put all the given values in the above formula, we get:
Thus, the concentration of is, 0.12 M
Explanation:
Copper(II) sulfide reacts with oxygen gas to give solid copper(II) oxide and sulfur trioxide gas.
The reaction is given as:
When 1 mol copper(II) sulfide react with 2 moles of oxygen gas it gives 1 mol of solid copper(II) oxide and 1 mol of sulfur trioxide gas
The gas formed in above reaction that is sulfur trioxide reacts with water to give sulfuric acid or hydrogen sulfate.
The reaction is given as:
1 mol of sulfur trioxide gas reacts with 1 mol of liquid water to produce 1 molo of liquid hydrogen sulfate or sulfuric acid
Answer:
Both are pure substances and a compound
