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Anna007 [38]
3 years ago
13

How many grams contained on 78.4 moles of neon

Chemistry
2 answers:
Natali [406]3 years ago
5 0
You have 3.498 moles of the gas/neon
Nikitich [7]3 years ago
5 0
You would have 1582.088 grams of neon
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Determine the mass of oxygen that is needed to react with 33 grams of phosphorus.
Kipish [7]

Answer:

D = Mass =  42.6 g

Explanation:

Given data:

Mass of phosphorus react = 33 g

Mass of oxygen needed = ?  

Solution:

Chemical equation:

4P + 5O₂     →      2P₂O₅

Number of moles of phosphorus:

Number of moles = mass/molar mass

Number of moles = 33 g/ 30.97 g/mol

Number of moles = 1.065 mol  

now we will compare the moles of phosphorus and oxygen.  

               P         :       O₂  

               4         :        5  

        1.065        :        5/4×1.065 = 1.33mol

Mass of oxygen needed:

Mass = number of moles × molar mass

Mass = 1.33 mol × 32 g/mol  

Mass = 42.6 g

Thus, 43.6 g of oxygen needed to react with 33 g of phosphorus.

8 0
3 years ago
I need help with this question please!!
mariarad [96]
The answer is B

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Convert 0.5 moles of oxygen to molecules of oxygen
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4 years ago
At catalyst is ______.
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Heya!!!

Answer to your question:

A catalyst is ______
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Catalyst do not change the amount of reactants or products or itself get used but it just change the rate of reaction.

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4 0
4 years ago
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