Answer:
In percentage, the sample of C-4 remains = 0.7015 %
Explanation:
The Half life Carbon 14 = 5730 year
Where, k is rate constant
So,
The rate constant, k = 0.000120968 year⁻¹
Time = 41000 years
Using integrated rate law for first order kinetics as:
Where,
is the concentration at time t
is the initial concentration
So,
<u>In percentage, the sample of C-4 remains = 0.7015 %</u>
Answer:
The molarity of the base is 0.2664 M
Explanation:
Firstly, we write the complete and balanced titration reaction.
+
→
+
From the reaction, we can identify that 1 mole of the acid reacted with 2 moles of the alkali (base) to yield salt and water only
We identify the following also from the question;
= 14.80 mL ,
= 25.00 mL ,
= 0.225M and
= ?
= 1 ,
= 2
We use the relation;
/
=
/
Plugging the values, we have ;
(0.225 × 14.80)/1 = ( × 25.00)/2
= (2 × 0.225 × 14.80)/25
= 0.2664 M