Explanation:
An ionic equation will be the one in which all the participating species will be present as ions.
The given reaction will be as follows.
Balancing this equation by multiplying 
by 2 and 
by 3 on reactant side. Whereas multiply KBr by 6 on product side.
Hence, the net ionic equation will be as follows.
As both 
and 
are spectator ions. Hence, the net ionic equation will be as follows.
Given molecule Lithium iodide (LiI)
Heat of hydration = -793 kj/mol
Lattice energy = -730 kJ/mol
Heat of hydration = Heat of solution - Lattice energy
Heat of solution = Hydration + Lattice = -793 + (- 730) = -1523 kJ/mol
Now,
Mass of LiI = 15.0 g
molar mass of LiI = 134 g/mol
# moles of LiI = 15/134 = 0.112 moles
Heat of solution for 1 mole of LiI = -1523 KJ
Therefore, for 0.112 moles of LiI the corresponding heat is
= 0.112 *(-1532) = 171.6 kJ
The name for NH3 is Nitrogen trihydride.
That number has 6 significant numbers. It's precision would be 602.
Hope it helped.
