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defon
3 years ago
7

How many moles in 500l of ar gas?

Chemistry
1 answer:
Alex3 years ago
8 0
Assuming conditions are at 25c and 1 bar 101.25 Kpa 1 mole of gas is equal to 22.4 L

So if you have 500L of ar gas the you have : 500L / 22.4 × 1 Mole = 22.3 moles of ar after accounting for sig figs..Hope that helps
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The practical limit to ages that can be determined by radiocarbon dating is about 41000-yr-old sample, what percentage of the or
Aloiza [94]

Answer:

In percentage, the sample of C-4 remains = 0.7015 %

Explanation:

The Half life  Carbon 14 =  5730 year

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

k=\frac {ln\ 2}{5730}\ hour^{-1}

The rate constant, k = 0.000120968 year⁻¹

Time = 41000 years

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

So,  

\frac {[A_t]}{[A_0]}=e^{-0.000120968\times 41000}

\frac {[A_t]}{[A_0]}=0.007015

<u>In percentage, the sample of C-4 remains = 0.7015 %</u>

3 0
3 years ago
A student does a titration with 14.80 mL of 0.225M H2SO4 and 25.00 mL of unknown LiOH solution. What is the molarity of the base
Degger [83]

Answer:

The molarity of the base is 0.2664 M

Explanation:

Firstly, we write the complete and balanced titration reaction.

H_{2}SO_{4(aq)}  +    2 LiOH_{(aq)}    →   Li_{2}SO_{4(aq)}   +   2H_{2}O_{(l)}

From the reaction, we can identify that 1 mole of the acid reacted with 2 moles of the alkali (base) to yield salt and water only

We identify the following also from the question;

V_{a} = 14.80 mL  , V_{b} = 25.00 mL , C_{a} = 0.225M and C_{b} = ?

n_{a} = 1 , n_{b} = 2

We use the relation;

C_{a}V_{a}/n_{a} = C_{b} V_{b}/ n_{b}

Plugging the values, we have ;

(0.225 × 14.80)/1 = ( C_{b} × 25.00)/2

C_{b} = (2 × 0.225 × 14.80)/25

C_{b} = 0.2664 M

8 0
3 years ago
For each (P, V) pair, type the pressure in the x-column and the volume in the y-column. Then click “Resize window to fit data.”
qwelly [4]

Answer:

V= 51.4   P^= -0.999

the second one is: an inverse proportion

Explanation:

Just did it on Edg

7 0
3 years ago
Suppose that 3.74 ml of carbon dioxide (C02) accidentally escaped during the experiment, what volume in liters would that be
Lynna [10]
2.5 is my best guess .-.
4 0
3 years ago
What is the frequency of green light that has a wavelength of 5.14 x 10^-7m?
nata0808 [166]

Answer:

Frecuency = 5,83x10⁻⁷ Hz

Explanation:

The equation that connects wavelenght and frequency is given by:

λ = c/ν

λ=wavelenght (expressed in lenght´s units)

c= speed of light (3x10⁸ m/sec)

ν=frequency (expressed in units of time⁻¹ or Herzt)

In our case, λ=5,14x10⁻⁷ m , so replacing in our previous formula, this gives us the final result of ν (frequency for green light) of 5,83x10¹⁴ Hz (or Herzt)

5 0
3 years ago
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