Answer:
it can help you with answer a math problem
Step-by-step explanation:
<span>Formula: H(t) = 56t – 16t^2
</span>
H(t) = - 16t^2 + 56t
<span><span>A.
</span>What is the height of the ball after 1 second? H
(1) = 56(1) – 16(1) ^2 = 40 pt.</span>
<span><span>B.
</span>What is the maximum height? X = - (56)/2(- 16) =
1.75 sec h (1.75) = 56(1.75) – 16(1.75) ^2 h (1.75) = 49ft.</span>
<span><span>C.
</span><span>After how many seconds will it return to the
ground? – 16t^2 + 56t = 0 - 8t =0 t = 0</span></span>
<span><span>-
</span><span>8t (2 + - 7) = 0 2t – 7 = 0 t = 7/2
Ans: 3.5 seconds</span></span>
Answer:
96 square units
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo.
My answer:
- The length of the large rectangle is: 5
- The width of the large rectangle is: 7
=> Area of the large rectangle = length × width = 7*5 = 35 square units
- The length of the middle rectangle is: 7
- The width of the middle rectangle is: 4
=> Area of the middle rectangle = length × width = 7*4 = 28 square units
- The length of the small rectangle is: 7
- The width of the small rectangle is: 3
=> Area of the small rectangle = length × width = 7*3 = 21 square units
Area of top and the bottom triangles =2*
Total surface area = 35 + 28 + 21 + 12 = 96 square units
Say that taking a quarter of student out of the group will add a quarter present of days for food so by take 20 students out you’ll get 60 days (that’s what I got hope this helps)
Answer:
f(x) is continuous on the interval [0, 1], f(0) = <u>-2</u> , and f(1) = <u>1.718</u> . Since f(0) < 0 < f(1) , there is a number c in (0, 1) such that f(c) = 0 by the Intermediate Value Theorem. Thus, there is a root of the equation ex = 3 − 2x, in the interval (0, 1)
Step-by-step explanation:
From the question we are told that
The equation is
The interval is [0, 1]
Generally f(0) is
=>
=>
Generally f(1) is
From the value we see that at x = 0 , f(0) = -2 which is below the x-axis
and the at x = 1 , f(1) = 1.718 which is above the x-axis
Now the according to Intermediate Value Theorem , given the condition stated above, there will exist a root c in the interval such that
f(c) = 0