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crimeas [40]
3 years ago
6

ANSWER QUICKLY AND CORRECT THEN I WILL GIVE BRIANLIEST. NO FAKE ANSWERS TO TAKE POINTS

Mathematics
1 answer:
vfiekz [6]3 years ago
7 0

Answer:

B. 14

Step-by-step explanation:

To determine whether a triangle or not, use the triangle inequality theorem. Two smaller sides must add up and be greater than the larger side.

13+7=20  wouldn't work

14+7>20 would work

7+20=27  wouldn't work

7+20<28   wouldn't work

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Find the x-intercept and the y-intercept without graphing. Write the coordinates of each intercept.
ANEK [815]

Answer:

Point of x-intercept: (2,0).

Point of y-intercept: (0,6).

Step-by-step explanation:

1. Finding the x-intercept.

This point is where the graph of the function touches the x axis. It can be found by substituting the "y" for 0. This is how you do it:

y=-3x+6\\ \\-3x+6=0\\ \\-3x=-6\\\\x=\frac{-6}{-3} \\ \\x=2

Hence, the point of x-intercept: (2,0).

2. Finding the y-intercept.

This point is where the graph of the function touches the y axis. It can be found by substituting the "x" for 0. This is how you do it:

y=-3(0)+6\\ \\y=6

Hence, the point of y-intercept: (0,6).

7 0
1 year ago
Read 2 more answers
Is 56 ft, 65 ft, 16 ft a right triangle
Debora [2.8K]
No, it isn't a right triangle.
7 0
3 years ago
Read 2 more answers
Anyone know the answer
kykrilka [37]
You would need to change the slope to -6 because perpendicular lines have opposite reciprocal slopes.
5 0
3 years ago
There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=
yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = \frac{12P4}{12^{4} }

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = \frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }

P(X=2) = 0.401

P(X=3) = \frac{4C3 * 12P2}{12^{4} }

P(x=3) = 0.025

P(X=4) = \frac{12}{12^{4} }

P(X=4) = 0.001

Mean, \mu = \sum xP(x)

\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879

Standard deviation, SD = \sqrt{\sum x^{2} P(x) - \mu^{2}}  \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2}  * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}

SD = 1.033

4 0
4 years ago
A stadium has 49 comma 000 seats. Seats sell for ​$35 in Section​ A, ​$30 in Section​ B, and ​$25 in Section C. The number of se
romanna [79]
A has 27,000 seats, B has 14,
200 seats, and C has 12,800 seats
8 0
3 years ago
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