We know the following:
Cylinder volume: V₁ = π r² h
Ball (sphere) volume:V₂ =

π r³
where:
V - volume
r - radius of base of cylinder and diameter of ball
h - height of cylinder.
R = 13 cm ⇒ r = 13 ÷ 2 = 6.5
π = 3.14
a) Since balls touch all sides of cylinder (as shown in image), it can be concluded that height of cylinder is equal to sum of diameters of 3 balls and that radius of base of cylinder is equal to radius of ball:
h = 3 × r = 3 × 13 cm = 39 cm
r = 6.5 cm
So,
V₁ = <span>π r² h
</span><span>V₁ = </span>3.14 × (6.5 cm)² × 39 cm
V₁ = 5,173.9 cm³
b. The total volume of three balls is the sum of volumes of each ball:
Vₐ = 3 × <span>V₂
</span>Vₐ = 3 × <span>

π r³
</span>Vₐ = 3 ×

3.14<span> (6.5 cm)³</span>
Vₐ = 3,449.3 cm³
c. Percentage of the volume of the container occupied by three balls ould be expressed as ratio of volume of three balls and volume of cylinder:
V =

×100
V =

×100
V = 0.6666 ×100
V = 66.66%
Answer:
Im not sure but i think its A=1, B=0, and C=9
Step-by-step explanation:
hope this helps
Answer:
In the given diagram the side opposite angle J is LR which is :
<h2>
Option D</h2>
You need to solve this "system of linear equations." In other words, find a point (x,y) that satisfies both 4x-3y=17 and 2x-5y=-11.
Try solution by elimination. Multiply the 2nd equation by -2 to obtain -4x+5y=22. Add this result to the 1st equation. I'd suggest you write this out to see what is happening.
4x-3y=17
-4x+10y=22
----------------
7y=39. Solving for y, we get y=39/7 (a rather awkward fraction).
Now find x. To do this, substitute 39/7 for y in either of the given equations. Solve the resulting equation for x.
Write your solution in the form (x, y): ( ? , 39/7).