Explanation:
[H+]=10^-pH
[H+]=10^-9.2
[H+]=6.031x10^-10
[OH-]=1x10^-14÷[H+]
[OH-]=1x10^-14÷[6.031x10^-10]
[OH-]= 1.66x10^-5
im pretty sure this is right
Surface runoff, its quite obvious in the picture
The largest amount of CO₂ produced when 2 moles of C₂H₂ reacted with 1 mole of O₂ is 0.8 mole
We'll begin by writing the balanced equation for the reaction. This is given below:
2C₂H₂ + 5O₂ —> 4CO₂ + 2H₂O
2 : 5
2 : 1
From the balanced equation above,
We can see that O₂ is the limiting reactant as lesser amount of it is available.
Finally, we shall determine the largest amount of CO₂ produced by using the limiting reactant as illustrated below:
From the balanced equation above,
5 moles of O₂ reacted to produce 4 moles of CO₂.
Therefore,
1 mole of O₂ will react to produce = 4/5 = 0.8 mole of CO₂.
Thus, the largest amount of CO₂ produced from the reaction is 0.8 mole
Learn more: brainly.com/question/25299182
The answer in this question is FALSE. Hydrogen atom has electronic configuration 1s^1. It needs only one more electron to make a closed sub-shell. Therefore, a stable hydrogen atom does not have an octet but a duplet. Therefore, the statement is false.
A kilometer is equal to 1000 meters and a meter is equal to 100 centimeters, so:
1 km = 100000 cm
1 cm = 0,00001 km
Just multiply or divide it by 100000.