Answer:
3b/20+4
Step-by-step explanation:
-2 + 2/5b - 1/4b + 6
Combine 2/5b and 1/4b to get 3/20b
-2 + 3/20b + 6
Add −2 and 6 to get 4.
4+3/20b
Answer:
x and y
Step-by-step explanation:
The area of the figure is 161
Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.
Answer:
0.02
Step-by-step explanation:
Hope this helps!
