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3 years ago

Read and write the number in two other forms 314,207

Mathematics

2 answers:

Allisa [31]3 years ago

5 0

Word Form:
three hundred fourteen thousand, two hundred seven
Expanded Form:
300,000+10,000+4,000+200+7

velikii [3]3 years ago

4 0

Answer:

⇒314,207(In International System) =Three Hundred fourteen Thousand two hundred Seven

⇒314207(In Expanded form)=3×100000+1×10000+4×1000+2×100+0×10+7×1

$=3 *10^5+1*10^4+4*10^3+2*10^2+7$

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Answer:

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If x is gallons of 20% moonshine, and y is gallons of 30% moonshine, then:

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3 years ago

A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe

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Answer:

Fencing required = 1586 m

Step-by-step explanation:

The given statements can be thought of a triangle $\triangle ABC$ as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

$\angle A =49^\circ$

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use Cosine Rule to find the third side.

Formula for cosine rule:

$cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

$\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m$

Perimeter of the triangle = Sum of three sides = AB + BC + AC

Perimeter of the triangle = 435 + 495 + 656 = 1586 m

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3 years ago