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sergey [27]
3 years ago
13

Help me answer this question please​

Mathematics
1 answer:
arlik [135]3 years ago
7 0

Answer:

f'(2) = 8

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Calculus</u>

The definition of a derivative is "the slope of the tangent line".

Derivatives of constants are 0.

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 3x² - 4x + 2

<u>Step 2: Find 1st Derivative</u>

  1. Basic Power Rule:                    f'(x) = 2·3x²⁻¹ - 1·4x¹⁻¹
  2. Simplify:                                    f'(x) = 6x - 4

<u>Step 3: Find tangent slope</u>

  1. Define:                    f'(x) = 6x - 4, x = 2
  2. Substitute:              f'(2) = 6(2) - 4
  3. Multiply:                  f'(2) = 12 - 4
  4. Subtract:                 f'(2) = 8

<u>Step 4: Identify</u>

f'(2) = 8 tells us that at <em>x</em> = 2, the slope of the tangent line is 8.

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Step-by-step explanation:

Step  1  :

           27

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Equation at the end of step  1  :

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3.2       Adding up the two equivalent fractions

(4x+27) - (131 • 4)     4x - 497

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Equation at the end of step  3  :

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Step  4  :

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Here's how:

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Now, on the left hand side, the  4  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

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Solving a Single Variable Equation :

4.2      Solve  :    4x-497 = 0

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Divide both sides of the equation by 4:

                    x = 497/4 = 124.250

One solution was found :

                  x = 497/4 = 124.250

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