45000 x 4 = 180,000
180,000 * 5 = 900,000 ml in 5 days
1 liter = 1000 ml
900,000 / 1000 = 900 liters of water
Answer:
look the photo
Step-by-step explanation:
..0000000000000000
Answer:
12 weeks
Step-by-step explanation:
set up a proportion of ounces/weeks = ounces/weeks
12/8 = 18/w
12w = 144
w = 12
Answer:
(1, 1), (2, 2), (-3, -3), (4, 4), (-5, -5)
Step-by-step explanation:
You get a straight line. As you can see in the picture, the figure lies in the first and third quadrant.
Let Xi be the random variable representing the number of units the first worker produces in day i.
Define X = X1 + X2 + X3 + X4 + X5 as the random variable representing the number of units the
first worker produces during the entire week. It is easy to prove that X is normally distributed with mean µx = 5·75 = 375 and standard deviation σx = 20√5.
Similarly, define random variables Y1, Y2,...,Y5 representing the number of units produces by
the second worker during each of the five days and define Y = Y1 + Y2 + Y3 + Y4 + Y5. Again, Y is normally distributed with mean µy = 5·65 = 325 and standard deviation σy = 25√5. Of course, we assume that X and Y are independent. The problem asks for P(X > Y ) or in other words for P(X −Y > 0). It is a quite surprising fact that the random variable U = X−Y , the difference between X and Y , is also normally distributed with mean µU = µx−µy = 375−325 = 50 and standard deviation σU, where σ2 U = σ2 x+σ2 y = 400·5+625·5 = 1025·5 = 5125. It follows that σU = √5125. A reference to the above fact can be found online at http://mathworld.wolfram.com/NormalDifferenceDistribution.html.
Now everything reduces to finding P(U > 0) P(U > 0) = P(U −50 √5125 > − 50 √5125)≈ P(Z > −0.69843) ≈ 0.757546 .
