Let a=price of adult ticket
let c=price of a child's ticket
start out by writing the following system of equations:
3a+4c=132
2a+3c=94
then, multiply the first equation by 2, and the second equation by 3 to get the following system of equations:
6a+8c=264
6a+9c=282
subtract the like terms to get the following equation:
-c=-18
divide both sides by -1 to get rid of the negative to get the price of a child's ticket to be $18. to find the price of an adult ticket, pick one of the original equations to substitute the 18 in for c to find a. for example:
2a+3c=94
2a+3(18)=94
2a+54=94
-54 -54
2a=40
2 2
a=20
or if you decide to use the other equation:
3a+4c=132
3a+4(18)=132
3a+72=132
-72 -72
3a=60
3 3
a=20
either way, you still get an adults ticket to be $20 and a child's ticket to be $18.
Y=3x + 8.25
...................
B = 100(1 + 0.04)^12 = 100(1.04)^12 = 100(1.601) = $160.10
Multiply exponents together if it is on another exponent
(8^2)^6= 8^12
The secant of an angle is <span>the ratio of the hypotenuse to the shorter side adjacent to an acute angle. It is the reciprocal of cosine function. Therefore, the correct answer from the choices is option B.
sec A = 26/24 =13/12
sec B = 26/10 = 13/5
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