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juin [17]
3 years ago
5

What is the measure of angle L in parallelogram LMNO?

Mathematics
2 answers:
lozanna [386]3 years ago
7 0

Answer:

C

Step-by-step explanation:

M<L= 40

Alex3 years ago
3 0
In a parallelogram, the opposite angles are equal

3x-20=2x
3x-2x=20
x=20

Hence, 
∠L=3(20)-20=60-20=40

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I need help to solve this problem Simplify (6^7)^3​
VMariaS [17]

Answer:

C.

Step-by-step explanation:

(6^7)^3 means (6^7)(6^7)(6^7).

When multiply numbers with same base, add the exponents.

6^(7+7+7)=6^(3*7)=6^(21).

In the beginning you could have just multiply 7 and 3 so the answer is 6^(21).

5 0
3 years ago
Read 2 more answers
Which values are solutions to the inequality below? √x &gt; 25?
dezoksy [38]

Answer:

C and D

Step-by-step explanation:

So basically when u square -5 or +5, u get 25 either way

And since the square root of x is greater than or equal to 25, u can use both of them for answers.

5 0
3 years ago
Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were 3 mill
abruzzese [7]

Answer:

V' = -0.11552 *V\\= -0.11552(1.8)\\ \\=-0.20794 million per year

Step-by-step explanation:

Given that oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were 3 million barrels of oil in the well; six years later 1,500,000 barrels remain.

i.e. if V stands for volume of oil, then

V' =kV\\dv/V= kdt\\ln V = kt+C\\V = Ae^{kt}

To find A and k

V(0) = A = 3 million

Hence V = 3e^{kt}

V(6) = 1.5

i.e. 1.5 = 3e^{6k}\\ln 1.5 =ln 3 +6k\\k = -0.11552

V(t) = 3e^{-0.11552t}

a) Using the above value of k , we have

V' = -0.11552 *V\\= -0.11552(1.8)\\ \\=-0.20794 million per year.

4 0
3 years ago
Help help help help help
Blizzard [7]

Answer:

x = 12

Step-by-step explanation:

Becuase 6/12 = 2 and 9 + 2 = 11

12

7 0
2 years ago
Last question and then I’ll take care of the rest on my own ^^^^
Bond [772]

Answer:

  (c)  5/2

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

  a^-b = 1/a^b

__

Using these rules, we can simplify the expression as follows:

  (5^-3)(2^2)(5^6)/((2^3)(5^2)) = (5^(-3+6-2))(2^(2-3)) = (5^1)(2^-1)

  = 5/2

6 0
2 years ago
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