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3 years ago

How much fabric is needed to create the sail below? 14ft by 9ft

Mathematics

2 answers:

tia_tia [17]3 years ago

7 0

126ft

Calculate area.

14 x 9 = 126

Mandarinka [93]3 years ago

4 0

126 ft of fabric.

Explanation:

14x9 or 10x9+4x9

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Hi! Please help me, will mark brainliest!

PIT_PIT [208]

Answer:

p(t) = 0 for t = 1

p(t) = 1 for t = 1/8 = 8^-1

Step-by-step explanation:

the graph you will have to do yourself.

just go there and type in

$- log_{8}(x)$

well, don't type "log" in letters.

you start by typing the "-" sign, and then you need to look up the functions by clicking on the "funcs" button and look for the log functions .

pick the

$log_{a}$

option. and then simply enter 8 as the first parameter in the {} brackets and x as the second in the () brackets.

and then you see.

any logarithm is 0 for x (or t) = 1.

because any a⁰ = 1.

and the logarithm gives you that exponent of the base number that leads to the given x value.

in other words : a logarithm is the inverse function of an exponential function.

the exponential function is

y = a^x

and the logarithm then determines

$x = log_{a}(y)$

that is all.

and

$- log_{8}(x) = 1$

means that the logarithm itself delivered -1.

and 8^-1 = 1/8

so, p(t) = 1 for t = 1/8

5 0

2 years ago

I need help with this assignment help

saw5 [17]

Table:

4 cups of water, 5 cups of flour.

9 cups of water, 10 cups of flour.

16 cups of water, 17 cups of flour.

29 cups of water, 30 cups of flour.

Equation:

f-1=w

Independent variable:

Dependent variable:

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3 years ago

Use the function below to find F(2) F(x)=1/3•4

Drupady [299]

Answer:

7477rurjerjrjjrjdjfid

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3 years ago

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$