Step-by-step explanation:
If a variables varies jointly, we can just divide it by the other variables in relation to it.
For example, since p variables jointly as q and square of r, then
where k is a constant
First, let find k. Substitute p= 200
q= 2, and r=3.
Now, since we know our constant, let find p.
Q is 5, and r is 2.
6 - p....p = 1.5
6 - 1.5 = 4.5
TRUE...because when u sub in 1.5 for p, the difference is 4.5, which is less then 5.
(30)(420) = 12000 - 600
12600 = 11400...incorrect
FALSE...because the product of 30 and 420 does not equal 600 less then 12000
16.3 + 11.9 < 27
28.2 < 27..incorrect
FALSE...because the sum of 16.3 and 11.9 is greater then 27
A. 35-14=21 hopes this helps
A second degree polynomial function has the general form:
, where
.
The leading coefficient is a, so we have a=-1.
5 is a double root means that :
i) f(5)=0,
ii) the discriminant D is 0, where
.
Substituting x=5, we have
f(5)=a(5)^2+b(5)+c,
and since f(5)=0, and a is -1 we have:
0=-25+5b+c
thus c=25-5b.
By ii)
.
Substituting a with -1 and c with 25-5b we have:
Finally we find c: c=25-5b=25-50=-25
Thus the function is
Remark: It is also possible to solve the problem by considering the form
directly.
In general, if a quadratic function has leading coefficient a, and has a root r of multiplicity 2, then its form is
