Answer:
To determine the x-intercept, we set y equal to zero and solve for x. Similarly, to determine the y-intercept, we set x equal to zero and solve for y. ...
To find the x-intercept, set y = 0 \displaystyle y=0 y=0.
To find the y-intercept, set x = 0 \displaystyle x=0 x=0.
Answer:
83.2 cm^2
Step-by-step explanation:
To solve this we're going to find the area of the bigger triangle (the shaded and unshaded parts together) and then the area of the smaller triangle (the unshaded part) and then subtract that from the area of the bigger triangle. We're going to use the equation: Area=1/2 x base x height. So the base of the big triangle is 16, and the height is (10.4+8.6 = 19). Put into the equation this looks like this: Area=1/2 x 16 x 19, so by multiplying we find that the area is 152 cm^2. Next we find the small triangle's area, Area=1/2 x 16 x 8.6, so the area is 68.8. Then to find the area of the shaded part, we subtract the unshaded area (68.8) from the whole area (152), 152-68.8=83.2.
The scale factor is six and the dilation is an enlargement.
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Answer:
w is the width
L is the length
p is the perimeter
w=9
L=27
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Step-by-step explanation:
p=2[(L-4) + (w+1)]
⇔p=2[(3w-4) + (w+1)]
⇔p=2[4w-3]
⇔p=8w-6
⇔66=8w-6
⇔8w=72
⇔w=9
Then L=3w=27
:)
Step-by-step explanation:
It is given that the angels of a triangle have a sum of 180°. The angles of a rectangle have a sum of 360°. The angels of a pentagon have a sum of 540.
<u>Let me define the each terms.</u>
1. We know that each angle in a triangle is 60°, So there is a three angle in a regular triangle.
2. We know that each angle in a rectangle, is 90°, So there is a four angle in a regular rectangle.
Similarly,
- There is 8 angle in a regular octagon and each angle measurement is 135°.
So, sum of the angles of an octagon = 135° × 8
Sum of the angles of an octagon = 1080°
Therefore, the required sum of the angles of an octagon is 1080°
