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34kurt
3 years ago
13

during her first six months, susie gained 25% more than her birth weight. if she gained 2 1/2 pounds during this period, how muc

h did she weigh at birth?
Mathematics
1 answer:
stich3 [128]3 years ago
6 0

Answer:

the answer is

25% = 2.5 pounds

25 x 4 = 100%

2.5 x 4 = 10 pounds

Step-by-step explanation:

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What is 3/4÷1/8 3/4÷1/8 explain or show your reasoning
Vikki [24]

Answer:

52.5

Step-by-step explanation:

it is simple. very simple

6 0
3 years ago
Read 2 more answers
Which answer is the best explanation for how to check to see that the difference has been calculated correctly for this problem?
scoundrel [369]
A. No, because if you add 76.5 and 4.32, you'll get 80.82 instead of 72.18.

B. Yes, because if you add 72.18 and 4.32 you'll get 76.5

C. No, because if you substract 4.32 from 72.18, you'll get 67.86 instead of 76.5.

D. No, because if you add 76.5 and 72.18, you'll get 144.65 instead of 4.32.

Correct answer: B
4 0
3 years ago
Find the area between the graph please
vagabundo [1.1K]

The area of the region shown in the coordinate plane is 2.7823 units square.

<h3>What is integration?</h3>

It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.

It is given that:

The graph of a function:

y = sinx

And a line segment passed through:

(0, 0) and (7π/6, -1/2)

First, find the equation of the line:

y = (-1/2)/(7π/6)[x]

y = (-3/7π)x

The area by definite integration:

\rm Area = \int\limits^{7\pi/6}_0 {[sinx - (-3/7\pi)x]} \, dx

\rm Area = \int\limits^{7\pi/6}_0 {[sinx +3x/7\pi ]} \, dx

After solving the above definite integral:

Area = 2.7823 units square

Thus, the area of the region shown in the coordinate plane is 2.7823 units square.

Learn more about integration here:

brainly.com/question/18125359

#SPJ1

4 0
2 years ago
Alexis divided a 13/4 pound bag of apples among her three friends.How manypounds of apples did each friend receive
Georgia [21]
\frac{13}{4} / 3\\=\frac{13}{4} \times \frac{1}{3}\\=\frac{13}{12}
7 0
3 years ago
I need help on question 7 and 8
DanielleElmas [232]
7.
remember
(ab)/(cd)=(a/c)(b/d)
we can split them up
and
(x^m)/(x^n)=x^(m-n)

\frac{27k^5m^8}{4k^3*9m^2}=  \frac{27k^5m^8}{36k^3m^2}=( \frac{27}{36} )( \frac{k^5}{k^3} )( \frac{m^8}{m^2} )=( \frac{3}{4})(k^{5-3})(m^{8-2} )=( \frac{3}{4})(k^2)(m^6 )= \frac{3k^2m^6}{4}



9.

2 to 3
4(x-1)=15
to
4x-1=15
the distribuutive prperty
a(b-c)=ab-ac
what he did was
a(b-c)=ab-c

he did not distribute the 4 to the -1


4(x-1)+3=18
minus 3
4(x-1)=15
distribute  4 to x and -1
4x-4=15
add 4 to both sides
4x=19
divide by 4
x=19/4
4 0
3 years ago
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