Using the regression formula with a slope = 2000 and intercept = 15000, what would the predicted income be for someone who has 16 years of education.
Natural number
that is 1,2,3,4,5,6...
It can have however many x intercepts it wants,
<span>BUT, to be a function it must pass the vertical line test. </span>
<span>this means you have to look at the graph and see if a vertical line drawn anywhere hits the graph more than once. </span>
<span>if it hits it more than once, it is NOT a function.
</span>
An example is a polynomial function to the infinite degree. That is
f(x) = lim (n --> infinity) [ x^n]
but only 1 y intercept (vertical line test remember)
The question is missing the graph. So, it is attached below.
Answer:
(D) 3.2
Step-by-step explanation:
Given:
A graph of height versus width.
The equation given is:
Height = constant × Width
Rewriting in terms of 'constant'. This gives,
------------- (1)
The width is plotted on the X-axis and the corresponding height is plotted on the Y-axis.
The four points plotted on the line are:
.
Now, any point will satisfy equation (1).
Consider the point (0.5, 1.6). So, height = 1.6 and width = 0.5. Therefore,
Also, we observe that for all the remaining points,
.
Hence, the value of the constant is 3.2.
Option (D) is correct.
Answer:
In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.
But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?
Thank you for all of the help.
That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)
So: the two events are not independent, and so that formula doesn't work.
Fortunately, a formula that does work (always!) is:
P(A∪B)=P(A)+P(B)−P(A∩B)
Hence:
P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330
