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3 years ago

G(x)=17-2/3x;g(6) please help me i only have 5 mins left

Mathematics

1 answer:

marishachu [46]3 years ago

4 0

Answer:

Step-by-step explanation:

17 - 2/3(6)

17 - 4

sub in 6 for x to find g(6) instead of g(x)

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Which of the following is the standard equation of the ellipse with vertices at (1,0) and (27,0) and an eccentricity of 5/13?

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The equation of an elipse of center $(x_0, y_0)$ is given by:

$\frac{(x - x_0)^2}{a^2} + \frac{(y - y_0)^2}{b^2} = 0$

Values a and b are found according to the <u>vertices and the eccentricity</u>.

It has vertices at (1,0) and (27,0), thus:

$x_0 = \frac{27 + 1}{2} = 14$

$y_0 = \frac{0 + 0}{2} = 0$

$a = \frac{27 - 1}{2} = 13$

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It has eccentricity of $\frac{5}{13}$ , thus:

$\frac{5}{13} = \frac{c}{a}$

$\frac{5}{13} = \frac{c}{13}$

$c = 13$

Thus, b is given according to the following equation:

$c^2 = a^2 - b^2$

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$b^2 = 169 - 25$

$b = \sqrt{144}$

$b = 12$

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$\frac{(x - 14)^2}{169} + \frac{y^2}{144} = 1$

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3 years ago

Write an equation of a line that is perpendicular to y = -5x + 2 and passes through (10,8).

andrew-mc [135]

Equation of required line is:

$y=\frac{1}{5}x+6$

Step-by-step explanation:

We need to write an equation of a line that is perpendicular to y = -5x + 2 and passes through (10,8).

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$y=mx+b$

Where m is the slope and b is the y-intercept

Comparing the given equation y = -5x + 2 with standard form:

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So, value of b=6

So, Equation of required line is:

$y=\frac{1}{5}x+6$

Keywords: Point slope form

Learn more about Point slope form at:

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