If dy/dx = tan(x), then y=

2 answers:

6 0

Dy/dx= tanx, can be answered directly using the derivatives of trigonometric functions but this is how the answer is derived
=(sinx/cosx) basic trigonometric function
= [cosx cox+sinxsinx]/cos^2x
=[cos^2x+sin^2x]/cos^2x
cos^2+sin^2x = 1 ; fundamental trigonometric identities
= 1/cos^2x; reciprocal relations
= sec^2x+C
The answer is letter B.sec^2x+C

harkovskaia [24]3 years ago

3 0

The answer to this question is:

<span>B) (sec x)^2 + C</span>

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2 years ago

Factor out the coefficient 1/2d+6

Ratling [72]

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2 years ago

Read 2 more answers

Type the correct answer in each box. A circle is centered at the point (5, -4) and passes through the point (-3, 2). The equatio

Galina-37 [17]

Answer:

$(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}$

Step-by-step explanation:

Given:

Center of circle is at (5, -4).

A point on the circle is $(x_1,y_1)=(-3, 2)$

Equation of a circle with center $(h,k)$ and radius 'r' is given as:

$(x-h)^2+(y-k)^2=r^2$

Here, $(h,k)=(5,-4)$

Radius of a circle is equal to the distance of point on the circle from the center of the circle and is given using the distance formula for square of the distance as:

$r^2=(h-x_1)^2+(k-y_1)^2$