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jarptica [38.1K]
3 years ago
10

How much is 50 meters in 1/2 minutes

Mathematics
2 answers:
UkoKoshka [18]3 years ago
3 0

Answer:S = Speed

D = Distance

T = Time

S = D/T

S = 50m/1/2

50 divided by 1/2 = 25

25 = 50/1/2

S = 25 m/min.

Step-by-step explanation:

Arlecino [84]3 years ago
3 0

Answer:

100

Step-by-step explanation:

I hope it helps u dear

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(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop
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Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})

Compute the sample sizes as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}

       n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}

          =\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

\hat p_{1}=0.45\\\hat p_{2}=0.58

Compute the sample size as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}

       n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}

          =\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666

Thus, the sample sizes are 6666.

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The answer would be A. 21 because 21/7 would equal 3
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