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makvit [3.9K]
3 years ago
14

Which set of coefficients will correctly balance the following skeleton equation?

Chemistry
1 answer:
slamgirl [31]3 years ago
5 0

Answer:

2Fe + 3Cl2 → 2FeCl3

Explanation:

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What happened to the amplitude from wave A to wave B?
dangina [55]
The amplitude doubled
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3 years ago
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Problem Page A gas made up of atoms escapes through a pinhole 0.225 times as fast as H2 gas. Write the chemical formula of the g
Tcecarenko [31]
To determine what gas is this, we use Graham's Law of Effusion where it relates the rates of effusion of gases and their molar masses. We do as follows:

r1/r2 = √(M2 / M1)

Let 1 be the the unkown gas and 2 the H2 gas.

r1/r2 = 0.225
M2 = 2.02 g/mol

0.225 = √(2.02 / M1)
M1 = 39.90 g/mol

From the periodic table of elements, most likely, the gas is argon.
5 0
3 years ago
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1.42 g H2 is allowed to react with 10.4 g N2 , producing 2.14 g NH3 . Part A What is the theoretical yield in grams for this rea
Bad White [126]

Taking into account the reaction stoichiometry, the theorical yield for the reaction is 8.0467 grams of NH₃.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

3 H₂ + N₂ → 2 NH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • H₂: 3 moles
  • N₂: 1 mole
  • NH₃: 2 moles

The molar mass of the compounds is:

  • H₂: 2 g/mole
  • N₂: 28 g/mole
  • NH₃: 17 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • H₂: 3 moles ×2 g/mole= 6 grams
  • N₂: 1 mole ×28 g/mole= 28 grams
  • NH₃: 2 moles ×17 g/mole= 34 grams

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 28 grams of N₂ reacts with 6 grams of H₂, 10.4 grams of N₂ reacts with how much mass of H₂?

mass of H_{2} =\frac{10.4 grams of N_{2}x 6 grams of H_{2} }{28 grams of N_{2}}

<u><em>mass of H₂= 2.2286 grams</em></u>

But 2.2286 grams of H₂ are not available, 1.42 grams are available. Since you have less mass than you need to react with 10.4 grams of N₂, H₂ will be the limiting reagent.

<h3>Definition of theorical yield</h3>

The theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

<h3>Theoretical yield in this case</h3>

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 6 grams of H₂ form 34 grams of NH₃, 1.42 grams of H₂ form how much mass of NH₃?

mass of NH_{3} =\frac{1.42 grams of H_{2} x 34 grams of NH_{3}}{6grams of H_{2} }

<u><em>mass of NH₃= 8.0467 grams</em></u>

Then, the theorical yield for the reaction is 8.0467 grams of NH₃.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

7 0
1 year ago
Pls help!!! ILL GIVE BRAINLIEST, 70 points + 10 more if not plagiarized ty ty (also for those who scam and do it for the points
sukhopar [10]

Answer:

What procedure did you use to complete the lab?

→Procedures that needs to be considered to complete the lab are- a thorough knowledge of lab assignments, knowledge about safety equipment, reviewing the MSDS of chemicals for lab experiment etc.

<h3>Explanation:</h3>

To be lab prepared one must follow these procedures-

1. One should have the knowledge of lab assignments to make the lab experiment easier.

2. To be aware about safety equipment and their uses in lab, like- the location of fire extinguisher in lab.

3. To know the steps of experiments to be performed

4. To fill notebook of lab with information regarding the experiment

5. One should review the data sheets of chemicals material safety.

6. To put on all the necessary dressings to perform experiment.

7. To have complete understanding about the experiment disposals.

7 0
2 years ago
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A 222 N force is required to keep an object moving along a circular path with a diameter of 11.6 m at a speed of 7.60 m/s. What
Arte-miy333 [17]

Answer:

m=22.3\ kg

Explanation:

The expression for centrifugal force is shown below as:-

F=\frac{m\times v^2}{r}

Where, m is the mass of the object = ?

v is the velocity of the object = 7.60 m/s

r is the radius

F is the force = 222 N

Diamter = 11.6 m

Radius = d/2 = 11.6 m/2 = 5.8 m

Applying the values in the above expression as:-

222=\frac{m\times {7.60}^2}{5.8}

57.76m=1287.6

m=22.3\ kg

7 0
3 years ago
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