32.8 g of Butane is required and 99.3 g of CO₂ is produced
<u>Explanation:</u>
The above mentioned reaction can be written as,
C₄H₁₀(g) + 13 O₂(g) → 4CO₂(g) + 5 H₂O(g) where ΔH (rxn)= -2658 kJ
It is given that 1.5 × 10³ kJ of energy is produced, the original reaction says that 2658 kJ of heat is produced, which means that less than one mole of butane is used in the reaction.
That is
of butane reacted
Now this moles is converted into mass by multiplying it with its molar mass = 0.564 mol × 58.122 g / mol
= 32.8 g of butane.
Mass of CO₂ produced = 0.564 ×44.01 g /mol × 4 mol
= 99.3 g of CO₂
Thus 32.8 g of Butane is required and 99.3 g of CO₂ is produced
Answer: It's only one proton in the middle of the red circle there's nothing outside it.
Explanation: I'm not sure sorry :|
hope this helps
BE CAREFUL! If it is a controlled lab wear saftey equiptment. But it can blow up. So careful...
There are 2 molecules of Carbon dioxide(CO2)
<h3>Further explanation</h3>
Given
Molecules of CO2
Required
The number of molecules
Solution
The coefficient of a molecule shows the number of that molecule, while the subscript after the name of the atom indicates the number of that atom in the molecule
Because there is a coefficient of 2 in front of the CO2 molecule, then the number of CO2 molecules is 2
Answer:
a item dropping
Explanation:
KE is movement and PE is height. As it's falling it gets KE and falls downward giving it more KE and less PE
