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Ksivusya [100]
3 years ago
11

Diamonds and graphite are both made of carbon atoms. Why do they have different properties?

Chemistry
1 answer:
AysviL [449]3 years ago
6 0
Answer: Graphite and Diamond are different because they have different structures. Both have Giant Covalent Structures resulting in very high melting temperatures.
Explanation: each carbon atom in Diamond has 4 covalent bonds with other Carbons, making it extremely strong and hard.
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For the reaction so3 + h2o h2so4, calculate the percent yield if 500. g of sulfur trioxide react with excess water to produce 57
Lelu [443]
The %  yield  if  500 g of  sulfur trioxide  reacted  with  excess  water to   produce  575 g  of  sulfuric  acid is calculated using  the  below  formula


%  yield = actual  yield/ theoretical  yield  x100

actual  yield =575 grams
to  calculate  theoretical  yield
find the  moles  of SO3   used =mass/molar  mass
=  500g/   80 g/mol =6.25  moles

SO3+H2O=H2SO4
by   use of  mole ratio  of SO3  :  H2SO4 which  is 1:1  the moles of H2SO4  is  also=  6.25  moles

the theoretical  yield of H2SO4 is therefore =  moles /molar  mass
=  6.25  x98=  612.5 grams

%yield  is therefore= 575 g/612 g   x100=  93.9  %

5 0
3 years ago
How do the molecules in a liquid behave?
inn [45]

Answer:

in a liquid, particles will flow or glide over one another, but stay toward the bottom of the container.

Explanation:

the attractive forces between particles are strong enough to hold a specific volume but not strong enough to keep the molecules sliding over each other.

7 0
4 years ago
Read 2 more answers
Mg(OH)2 + 2 HBr à MgBr2 + 2 H2O
AnnyKZ [126]

Explanation:

The balanced equation of the reaction is given as;

Mg(OH)2 (s) + 2 HBr (aq) → MgBr2 (aq) + 2 H2O (l)

1. How many grams of MgBr2 will be produced from 18.3 grams of HBr?

From the reaction;

2 mol of HBr produces 1 mol of  MgBr2

Converting to masses using;

Mass = Number of moles * Molar mass

Molar mass of HBr = 80.91 g/mol

Molar mass of MgBr2 = 184.113 g/mol

This means;

(2 * 80.91 = 161.82g) of HBr produces (1 * 184.113 = 184.113g) MgBr2

18.3g would produce x

161.82 = 184.113

18.3 = x

x = (184.113 * 18.3 ) / 161.82 = 20.8 g

2. How many moles of H2O will be produced from 18.3 grams of HBr?

Converting the mass to mol;

Number of moles = Mass / Molar mass = 18.3 / 80.91 = 0.226 mol

From the reaction;

2 mol of HBr produces 2 mol of H2O

0.226 mol would produce x

2 =2

0.226 = x

x = 0.226 * 2 / 2 = 0.226 mol

3. How many grams of Mg(OH)2 are needed to completely react with 18.3 grams of HBr?

From the reaction;

2 mol of HBr reacts with 1 mol of Mg(OH)2

18.3g of HBr =  0.226 mol

2 = 1

0.226 = x

x = 0.226 * 1 /2

x = 0.113 mol

5 0
3 years ago
What are some of the benefits of using measurements to find density? Provide 2 each. What are some of the challenges of using me
stellarik [79]

Some of the benefits of using measurements to find density include the following:

  • It is easy and doesn't require experiments.
  • The volume of both light and dense molecule can be gotten.

Some of the challenges of using measurements to find density include the following:

  • Inconsistency in the grind setting
  • Temperature changes not taken into account.

<h3>What is Density?</h3>

This is defined as the mass per unit volume of a substance or te degree of compactness of a substance and can be gotten with the use of measurements or experiments.

The measurement doesn't take the temperature changes into consideration which will lead to the result being most likely incorrect. It is also advantageous because less time is used thereby making it easier.

Read more about Density here brainly.com/question/406690

#SPJ1

7 0
2 years ago
How does your body respond differently the second time it is exposed to a pathogen than the first time it was exposed to the sam
LiRa [457]
After your first exposure to a pathogen, you have memory T cells that will remember the antigen of the pathogen son in the future if you would come in contact with the same pathogen your body will recognize it right away and be able to kill it much faster
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