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masya89 [10]
2 years ago
12

In a large population, 57 % of the people have been vaccinated. If 5 people are randomly selected, what is the probability that

AT LEAST ONE of them has been vaccinated?
Mathematics
1 answer:
My name is Ann [436]2 years ago
5 0

Answer:

0.986

Step-by-step explanation:

Probability of at least one being vac = 1 - Probability of all 5 not vac

1 - (1-0.57)^5 = 1 - (0.43^5) = 1 - 0.014 = 0.986

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Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)
Leni [432]
Alrighty

remember some rules
(ab)^c=(a^c)(b^c)
and
x^{-m}=\frac{1}{x^m}
and
x^0=1 for all real values of x
and
(a^b)^c=a^{bc}
and
(\frac{a}{b})^c=\frac{a^c}{b^c}
and
(a/b)/(c/d)=(ad)/(bc)
and
(a^b)(a^c)=a^{b+c}
and
\frac{a^m}{a^n}=a^{m-n}
and don't forget pemdas
example: -x^m=-1(x^m) but (-x)^m=(-1)^m(x^m)

so

4.
(\frac{c^{-2}}{2})^{-2}=

\frac{(c^{-2})^{-2}}{2^{-2}}=

\frac{c^4}{\frac{1}{2^2}}=

\frac{c^4}{\frac{1}{4}}=

4c^4



5.

\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=

\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=

\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=

\frac{(a^4bc^5)b^3}{(-1)(a^2)}=

\frac{-a^4b^4c^5}{a^2}=

-a^2b^4c^5
3 0
3 years ago
What is the approximate volume of the cone?
Vlad [161]
Volume=1/3π<span>×</span>r²×h^(Applies for any "right cone")^
Therefore your answer would be 
A.1206 cm³

8 0
3 years ago
Read 2 more answers
Let g represent the minimum amount of money Jamie needs to earn to pay his bills. Jamie works part time at an accounting firm. H
inessss [21]

Jamie has earned $80 +75 +145 +250 +80 = $630 so far this week. He needs to earn an additional $875 -630 = $245 to pay his bills.

If Jamie only has one last task, he must earn $245 on that task to pay his bills this week.

7 0
3 years ago
Someone help me please
Gemiola [76]

Answer:

x=2\sqrt{6}

Step-by-step explanation:

Use the Pythagorean theorem:

a^2+b^2=c^2

a and b are the legs and c is the hypotenuse. Insert the values:

\sqrt{10}^2+\sqrt{14}^2=x^2

Simplify exponents using the rule \sqrt{x}^2=x :

10+14=x^2

Simplify addition:

24=x^2\\x^2=24

Find the square root:

\sqrt{x^2}=\sqrt{24}\\  x=\sqrt{24}

Simplify in radical form: Find a common factor of 24 that is a perfect square:

\sqrt{24}=\sqrt{4*6}

Separate:

\sqrt{4}*\sqrt{6}

Simplify:

2*\sqrt{6}\\x=2\sqrt{6}

Finito.

3 0
3 years ago
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Is this shape a polygon?
Allushta [10]
No its not  polygons dont cross lines 

8 0
3 years ago
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