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Alex
3 years ago
15

What Is The Similarity Between 85,17,19,4,2

Mathematics
1 answer:
aalyn [17]3 years ago
8 0
If a(n) = (39n^4 -506n^3 + 2341n^2 - 4610n + 3416) / 8 then 

<span>a(1) = 85 </span>
<span>a(2) = 17 </span>
<span>a(3) = 19 </span>
<span>a(4) = 4 </span>
<span>a(5) = 2</span>
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Write a formula for g(x) in terms of x.
liberstina [14]

The formula of g(x) is g(x) = -0.8x - 1.6

<h3>How to determine the formula of g(x)?</h3>

The equation is given as:

-4x - 6 = 5y + 2

Subtract 2 from both sides

5y = -4x - 8

Divide through by 5

y = -0.8x - 1.6

Express as a function

g(x) = -0.8x - 1.6

Hence, the formula of g(x) is g(x) = -0.8x - 1.6

Read more about linear functions at:

brainly.com/question/4025726

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3 0
1 year ago
Please Help..........................
jasenka [17]
The exact circumference is 60ft
8 0
4 years ago
Read 2 more answers
Find two numbers whose sum is 50 and whos difference is 22
pentagon [3]

Answer:

36 and 14

Step-by-step explanation:

Create an equation

x+x-22=50

Combine like terms

2x-22=50

Add 22 on both sides

2x=72

divide 72 by 2

x=36

subtract 22 from 36

14+36=50

Hope this helps! :P

5 0
3 years ago
Read 2 more answers
11 4/7 as an improper fraction​
ivolga24 [154]

Answer:

114 is an improper fraction as numerator 11 is greater than 4, the denominator. Step 2: We divide 11 by 4, and get 2 as a quotient and 3 as a remainder which is written as proper fraction 34.

3 0
3 years ago
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Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z
dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0  } \atop {0}; Otherwise} \right.

The value of constant C can be obtained as:

\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1

\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz  }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ])  } \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}]  } \, dy  }) \, dx =1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0  }) \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}]   } \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}]  } \, dx = 1

50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1

50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1

50C[0+\frac{1}{0.5} ] =1

100C = 1 ⇒ C = \frac{1}{100}

C = 0.01

3 0
3 years ago
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