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3 years ago

Find the value of x in the isosceles triangle shown below

Mathematics

1 answer:

levacccp [35]3 years ago

4 0

Answer:

x=10

Step-by-step explanation:

$\frac{x}{2}=\sqrt{13^2-12^2} \\x=2\sqrt{169-144} \\x=2\sqrt{25} \\x=2 \times 5=10$

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Andru [333]

Answer:

It is the third answer.

Step-by-step explanation:

When you are doing a math equation where you are pluggin in information the key is to just take it slow and look at it. Also for multiple choice questions just try every problem till one works.

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3 years ago

Solve for x: x/2x+3 + 2x+3/x = 184/65

Marat540 [252]

Answer:

x/2x+3 + 2x +3/x = 184 /65

x(2x + 3)–1 + (2x+3)x-1 = 184/65

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2x² + 3x / 2x² + 3x = 184/65

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2 years ago

Read 2 more answers

What do you know abou the graph of y=5 ?

Alisiya [41]

Answer:

Step-by-step explanation:

Solution : The graph of y=5 is a line parallel to the x-axis at a distance of 5 units from the origin

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3 years ago

Solve this please show your work <3

Nookie1986 [14]

Given:

The expression is

$\sqrt[3]{48}=\sqrt[3]{8\cdot \_\_}=$

To find:

The simplified form of the expression.

Solution:

We have,

$\sqrt[3]{48}=\sqrt[3]{8\cdot \_\_}=$

The expression $\sqrt[3]{48}$ can be written as

$\sqrt[3]{48}=\sqrt[3]{8\cdot 6}$

$\sqrt[3]{48}=\sqrt[3]{8}\cdot \sqrt[3]{6}$ $[\because \sqrt[3]{ab}=\sqrt[3]{a}\sqrt[3]{b}]$

$\sqrt[3]{48}=2\cdot \sqrt[3]{6}$

$\sqrt[3]{48}=2\sqrt[3]{6}$

Therefore, $\sqrt[3]{48}=\sqrt[3]{8\cdot 6}=2\sqrt[3]{6}$ .

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3 years ago

1 4 cm 4 cm 5 cm 3 cm Perimeter: Area:

ohaa [14]

Answer:

Step-by-step explanation:

840

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3 years ago

Find the value of x in the isosceles triangle shown below​

Find the value of x in the isosceles triangle shown below