Answer:
64k^2 - 16k +1
Step-by-step explanation:
We can rewrite this as
(-8k+1) ^2
We know that (a+b)^2 = a^2 +2ab +b^2
Let a = -8k and b = 1
(-8k+1) = (-8k)^2 +2*(-8k)(1) + 1^2
=64k^2 - 16k +1
we are given
now, we can find x , y and z components
Arc length calculation:
we can use formula
now, we can plug these values
now, we can simplify it
now, we can solve integral
now, we can plug bounds
and we get
so,
..............Answer
Answer:
Please post a picture of the given triangle.
Step-by-step explanation:
Answer:
a
Step-by-step explanation:
Recall that the "point-slope" form of a linear equation may be expressed as
y = mx + b,
where m is the gradient.
If m is negative, the gradient is negative.
If m is positive, the gradient is positive.
In our case, if we consider option A,
x + 3y = -2 (rearranging)
3y = -x -2
y = (-1/3) x - (2/3)
if we compare this to the general equation at the top, we can see that
gradient, = m = (-1/3) which is negative.
hence option a has a negative gradient.
