Question

The midpoint of the segment joining points (a, b) and (j, k) is:

Answer 1

Answer: $(\dfrac{j+a}{2},\dfrac{k+b}{2})$.

Step-by-step explanation:

The mid point (x,y) of the line joining the points (a,b) and (c,d) is given by :-

$(x,y)=(\dfrac{a+c}{2},\dfrac{b+d}{2})$

Let the midpoint of the segment joining points (a, b) and (j, k) be (x,y).

On the same criteria, the  midpoint of the segment joining points (a, b) and (j, k) is given by :-

$(x,y)=(\dfrac{a+j}{2},\dfrac{b+k}{2})$

Which can be written as

$(x,y)=(\dfrac{j+a}{2},\dfrac{k+b}{2})$

Hence, the correct option is $(\dfrac{j+a}{2},\dfrac{k+b}{2})$.