Based on the given condition, since the rectangle is inscribed in a circle given the length to be 3x, the width can be approximated by taking the right triangle formed by the radius and the w/2, sin 45 = w/2/r, which is equal to w = 2r sin45, therefore the Area of the inscribed rectangle = LxW = (3x)(2rsin45)
Answer:
the third one
Step-by-step explanation: hope this helps <3 :)
The answer is (-6, 5) for K.
In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.
(Kx + Lx)/2 = Mx
(Kx + 8)/2 = 1
Kx + 8 = 2
Kx = -6
And now we do the same thing for y values
(Ky + Ly)/2 = My
(Ky + -7)/2 = -1
Ky + -7 = -2
Ky = 5
This gives us the final point of (-6, 5)
