Y=-x+8
gradient of the parallel line is the same as the gradient of the line given, which is -1
to find the y-intercept, sub the values (9,-1) into the equation we are finding which is y=-x+c
The x value of the vertex in
ax^2+bx+c is -b/2a
y value is just sub for x
3x^2-6x+5
x value of vertex is -(-6)/(2*3)=6/6=1
sub back
y=3(1)^2-6(1)+5
y=3(1)-6+5
y=3-1
y=2
vertex is (1,2)
Answer:
V=10−3y
Step-by-step explanation:
Solve for V by simplifying both sides of the equation, then isolating the variable.
Consider a system of inequalities
Consider inequality in two variable
1. a x + b y ≤ c
2 . p x + q y ≥ r 3. x ≥ 0 4. y≥ 0
By drawing the graph ,You can find the region bounded by inequality 1, then reason bounded by inequality 2 , and then you can find the region common to both the inequality.
Consider the given inequality
x + y ≤2
x + y ≥1,
x≥ 0, y≥0.
You can find the solution below.
So, the Statement, To solve a system of inequalities graphically, you just need to graph each inequality and see which points are in the overlap of the graphs is True.