Answer:
simple, Volt =change in potential energy/Charge
the unit of energy is newton meter (Force*distance)
the unit of charge is coloumb
So, Volt/meter=newton* meter/coloumb*meter
=newton/coloumb (hence proved)
This unit is the potential drop per unit of length in a conductive wire with uniform resistance
Answer:
-0.1875 V.
Explanation:
Using
E₂ = MdI₁/dt........................ Equation 1
Where E₂ = Voltage induced in the second coil, M = mutual inductance of both coil, dI₁ = change in current in the first coil, dt = change in time.
Given: M = 3.00 mH = 0.003 H, dI₁ = (0-2.50) = -2.5 A, dt = 40 ms = 0.04 s.
Substitute into equation 1
E₂ = 0.003(-2.5)/0.04
E₂ = -0.1875 V.
Hence the induced emf = -0.1875 V.
Answer:V₁=300ml
T₁=27°C
V₂=?
T₂= -3°C
as we know
V₁T₁=V₂T₂
By putting values in formula
300ml×27°C=V₂×(-3°C)
300ml×27°C/-3°C=V₂
8100ml/-3=V₂
-2700ml=V₂
or V₂= -2700ml
The answer is Near Earth Objects (NEOs).
Near Earth Objects (NEOs) have gained particular interest to scientists in their observations because of its potential threats to the Earth. It can be comets or asteroids. It is called Near Earth since their orbits are too close to cross the orbit of the Earth thus NEO can reach the space near-Earth that more likely give potential threats to the Earth.
Answer:
it's a little hard I may help you after
